Each week 9 3/4 dozen eggs are sold.How long will 95 1/2 dozen eggs last?

Mathematics

1 answer:

iris [78.8K]3 years ago

4 0

Answer:

it will be approximately 10 weeks

Step-by-step explanation:

You might be interested in

To solve 493x = 3432x 1, write each side of the equation in terms of base.

iVinArrow [24]

The solution of the equation in terms of the base is $\rm x = \dfrac{-1}{2939}\\\\$ .

Given that

Equation; $\rm 493x= 3432x+1$

We have to find

The solution of the equation in terms of base.

According to the question

To determine the solution of the equation following all the steps given below.

Equation; $\rm 493x= 3432x+1$

Then,

$\rm 493x= 3432x+1\\\\493x-3432x=1\\\\-2939x=1\\\\x = \dfrac{-1}{2939}\\\\$

Hence, the solution of the equation in terms of the base is $\rm x = \dfrac{-1}{2939}\\\\$ .

To know more about Equation click the link given below.

brainly.com/question/12179591

7 0

3 years ago

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's ru

aleksandrvk [35]

Answer:

Step-by-step explanation:

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by

bn=(n)^(5.6/n).

$L = \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }$

Log on both sides

$In (L) = \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)$

$=5.6 \lim_{n \to \infty} \frac{d}{dn} In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1$