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Y_Kistochka [10]
3 years ago
7

The graph shows the relationship between the total cost and the number of gift cards that Raj bought for raffle prizes.

Mathematics
2 answers:
BabaBlast [244]3 years ago
6 0

<u>The problem is as following:</u>

The graph shows the relationship between the total cost and the number of gift cards that Raj bought for raffle prizes. What would be the cost for 5 of the gift cards? $80, $90, $100 Or $110

===============================================================

<u>Solution</u>:

The points of the figure represents a straight line

The general form of the straight line is  ⇒ y = mx + c

where m is the slope and c is constant

let x ⇒ The number of gifts cards , y ⇒ Total cost (in $)

we will find m and c using the points (1,20) , (2,40)

The slope = m = \frac{y_{2} - y_{1}}{x_{2}-x_{1}} =\frac{40-20}{2-1} =\frac{20}{1}=20

∴ y = 20x + c

Substitute with the point (1,20) ⇒ y = 20 at x = 1

∴ 20 = 20 * 1 + c

∴ 20 = 20 + c

∴ c = 0

∴ The equation of the line ⇒⇒⇒ y = 20x

To find the cost for 5 of the gift cards substitute with x = 5

∴ y = 20 * 5 = 100

So, the cost for 5 of the gift cards = $100

<u>The correct answer is option 3 ⇒⇒⇒ $100</u>

anygoal [31]3 years ago
3 0

Answer:

C:100

Step-by-step explanation:

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vampirchik [111]

As the sample size n is less than 30 normal distribution is used.

The values of x are converted into z by using the formula z= x-u/ s and then the z values are found out from the table.

The limits are found by using the formula x±σz or x±sz where s= σ

As the sample size is 10 which is less than 30 the normal distribution is used.

The probability of x< 2.59 is 0.3446

The probability 2.60<X <2.63 is 0.9484

So lower and upper limits are 2.607 and 2.612

Part A

As the sample size is 10 which is less than 30 the normal distribution is used.

Part B

For given value of x= 2.59 z is obtained =0.4

x= 2.59

z= x-u/ s

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Part C

For two given values of x= 2.60 and 2.63 z is obtained as =0.2 and 0.4

x1= 2.60

z1= x-u/ s

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z= -0.01/0.05

z=- 0.2

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z= 2.63-2.61/0.05

z= 0.02/0.05

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P (2.60<X<2.63) = P(-0.2 <Z<0.4)

= P(-0.2 <Z<0)+ P(0 <Z<0.4)

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The probability 2.60<X <2.63 is 0.9484

Part D"

p= 0.57

From the table z= 0.045

z= x-u/ s

zs= x-u

zs+u = x

x1= 0.045*0.05 +2.61= 2.61225

x2= 2.61- 0.00225= 2.60775

So lower and upper limits are 2.607 and 2.612

For further understanding of probability calculation click

brainly.com/question/25638875

#SPJ1

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