All categories

2 years ago

2.3×10⁹=(1×10³)(2.3×10^n)

Mathematics

1 answer:

kotegsom [21]2 years ago

5 0

Answer:

n = 6

Step-by-step explanation:

2.3 × $10^{9}$ = (1 × 10³)(2.3 × $10^{n}$ )

(1 × 10³)(2.3 × $10^{n}$ ) = (1)(2.3) × (10³)( $10^{n}$ ) = 2.3 × $10^{3+n}$

2.3 × $10^{3+n}$ = 2.3 × $10^{9}$ ⇒ 3 + n = 9 ⇒ n = 6

You might be interested in

HELP ME........................................................................

GaryK [48]

Answer: 17
2^2 is 4
45/9 is 5
Multiply 4•5 to get 20
Subtract 3

8 0

2 years ago

Read 2 more answers

Yuhh get in too ittt

DanielleElmas [232]

Answer:

Step-by-step explanation:

16x-16=4y

4(4x-4)=4y

y=4x-4

Therefore, the correct answer is choice A. Hope this helps!

7 0

3 years ago

Read 2 more answers

Two different floor plans are being offered in a new housing development. Several prospective buyers from three different age gr

zepelin [54]

Answer:

0.677

Step-by-step explanation:Add up the values in the plan A column. There are 10+12+16 = 38 people who prefer plan A.

Add up the values in the "40-49" row to find that 16+8 = 24 people are ages 40 to 49.

We have 38+24-16 = 46 people who either prefer plan A, are aged 40-49, or fit both descriptions. I subtracted off 16 because those 16 people were counted twice when adding 38 and 24.

An alternative way to get this value of 46 is to add up everything that is in column1 or row 3 (or both). So that would get 10+12+16+8 = 46.

Now add up everything in the table to find out how many people were surveyed total. That would be 10+7+12+15+16+8 = 68 people overall.

The probability of someone liking plan A, or being age 40-49, or both is 46/68 = 0.6765 approximately. Rounding to 3 decimal places gives 0.677

3 0

2 years ago

Which pair of triangles can be proven congruent by SAS?

Vlada [557]

Triangle B can be proven congruent

8 0

2 years ago

Read 2 more answers

The federal government would like to test the hypothesis that the average age of men filing for Social Security is higher than t

mixas84 [53]

Answer:

The 90% confidence interval is $-0.3433< \mu_1 - \mu_2 < 2.1433$

Step-by-step explanation:

From the question we are told that

The sample mean for men is $\= x_1 = 64.5 \ years$

The sample mean for women is $\= x_2 = 63.6 \ years$

The sample size for men is $n_1 = 35$

The sample size for women is $n_2 = 39$

The standard deviation for men is $s_1 = 3.0$

The standard deviation for women is $s_2 = 3.5$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s_1^2 }{n_1} + \frac{s_2^2}{n_2} }$

=> $SE = \sqrt{\frac{3^2 }{35} + \frac{3.5^2}{39} }$

=> $SE = 0.7558$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * SE$

=> $E = 1.645 * 0.7558$

=> $E = 1.2433$

Generally 90% confidence interval is mathematically represented as

$(\= x_1 - \= x_2) -E < \mu_1 - \mu_2 < (\= x_1 - \= x_2) -E$

=> $(64.5 - 63.6) -1.2433< \mu_1 - \mu_2$

=> $-0.3433< \mu_1 - \mu_2 < 2.1433$

7 0

2 years ago

2.3×10⁹=(1×10³)(2.3×10^n)​

2.3×10⁹=(1×10³)(2.3×10^n)