Answer:
h'(t) = (√t)(1 -5t²)/(2t)
Explanation:
First of all, your product rule needs to be written correctly.
(f(x)g(x))' = f'(x)g(x) +f(x)g'(x)
You have ...

Answer:
this pic is to blury sorry
Explanation:
Answer:
30888*10^8
Explanation:
concept used
law of exponent

____________________________
1.32 x 10^8 X 2.34 10^4
multiplying 1.32 and 2.34 we have
1.32*2.34 = 3.0888
10^8 X 10^4 = 10^(8+4) = 10^12
thus,
1.32 x 10^8 X 2.34 10^4 = 3.0888*10^12
3.0888 can be written as 30888/10000
1.32 x 10^8 X 2.34 10^4 = 30888/10000*10^12
10000 = 10^4
1.32 x 10^8 X 2.34 10^4 = (30888/10^4)*10^12
concept used now

1.32 x 10^8 X 2.34 10^4 = 30888*10^(12-4)
1.32 x 10^8 X 2.34 10^4 = 30888*10^8
thus, answer is 30888*10^8
The easiest way to find such limits, where there is a numerator and a denominator is to apply <span><span>Hospital's Rule.
1st find the derivative of the numerator and the derivative of the denominator, if it still gives an indeterminate value, find the second derivative of N and D
3) lim sin(2x)/x when x →0
Derivative sin2x → 2cos2x
Derivative x→ 1
2cos2x/1 when x→0 , 2cos2x → 2
and lim sin(2x)/x when x →0 is 2
4) lim(sinx)/(2x²-x)
→cosx/(2x-1) when x →0 cosx/(2x-1) = -1
and lim(sinx)/(2x²-x) when x →0 is -1
and so on and so forth. Try to continue following the same principle
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sorry but don't know the answer
but can you talk to me sorry