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atroni [7]
3 years ago
11

What is the common difference of the arithmetic sequence 5,8,11,14?

Mathematics
2 answers:
allsm [11]3 years ago
8 0

Answer:

3

Step-by-step explanation:

8-5= 3

11-8= 3

14-11= 3

Nataly_w [17]3 years ago
8 0

Answer:

common difference = difference between two consecutive number in a given series

hence,

8-5=3

common difference =3

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PLS HELP ILL MARK BRAINLIEST
stiv31 [10]

Answer:

210=75x-10x+35

Step-by-step explanation:

So we know to total profit he made is 210 dollars, in which he earned from 3 independent reasons.

The profits he made in per appointment will need a variable because we don't know how many appointments he made. So knowing that we can conclude that 75 dollars and 10 dollars per appointment has to have a variable after it. The same variable as well because both of which are money.

As of the tip, we don't need a variable because it is a one time addtion, he recieved a total of 35 dollars after all of the appointments, so no need to know how many. We already know the total.

So that leaves us to write an equation. The total=$per appointment-fee per appointment+tip. Which becomes 210=75x-10x+35.

Hope this helps!                                          

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3 years ago
PLZ HELP ;-;
Vaselesa [24]
The answer is x=6 and y=4.

6+4=10

and 8 times 6 + 12 times 4 is 96.
4 0
3 years ago
Read 2 more answers
More Literal Expressions, please include the way you worked out.
Artyom0805 [142]

A=h/2(a+b) solver for h

2A=h(a+b)

2A/(a+b)=h   (Solution)

4 0
3 years ago
Point A is located at (2, 3) on the coordinate plane. Point A is reflected over the x-axis to form point B and over the y-axis t
Mademuasel [1]

Answer:

Rectangle

Step-by-step explanation:

Well if point A is on (2,3) and you reflect it over the x axis point B would be located at (2,-3).

Then over the y axis point C would be located at (-2,-3), then reflecting that over the x axis point D is (-2,3)

<em><u>Points</u></em>

__________

A. (2,3)

B. (2,-3)

C. (-2,-3)

D. (-2,3)

__________

So graphing all these points we get a rectangle.

Because it has 4 sides that are 90 degrees and the sides opposite from each other are the same.

7 0
3 years ago
Find a point on the ellipsoid x2+y2+4z2=36x2+y2+4z2=36 where the tangent plane is perpendicular to the line with parametric equa
Anvisha [2.4K]

Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) :x^2+y^2+4z^2=36

Parametric equations:

x=-4t-1

y=2t+1

z=8t+3

Finding the gradient of function

\nabla f(x,y,z)=\\\nabla f(x,y,z)=

So, The directions vectors=(-4,2,8)

Now the line is perpendicular to plane when direction vector is parallel to the normal vector of line

\nablaf(x,y,z)=(2x,2y,8z)=\lambda(-4,2,8)

So, 2x=-4\lambda

\Rightarrow x=-2\lambda

2y=2\lambda\\\Rightarrow y=\lambda\\8z=8\lambda\\\Rightarrow z=\lambda

Substitute the value of x , y and z in the ellipsoid equation

(2\lambda)^2+(\lambda)^2+4(\lambda)^2=36\\9(\lambda)^2=36\\\lambda^2=4\\\lambda=\pm 2

With \lambda = 2

x=-2(2)=-4

y=2

z=2

With\lambda =- 2

x=-2(-2)=4

y=-2

z=-2

Hence a point on the ellipsoid is (-4,2,2) or (4,-2,-2)

7 0
3 years ago
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