Question

PLEASE HELP ME WITH THIS ALGEBRA QUESTION!! THANK YOU!!

Answer 1

Answer:

The first four terms of the sequence are: {-10,-23,-62,-179}

Step-by-step explanation:

Given recursive formula is:

$a_n = 3a_{n-1}+7$

First term = a1 = -10

The first term is already known. In order to find the next terms, we will put n=2,3,4 in the recursive formula.

Putting n=2

$a_2 = 3a_{2-1}+7\\a_2 = 3a_1+7\\a_2 = 3(-10)+7\\a_2 = -30+7\\a_2 = -23$

Putting n=3

$a_3 = 3a_{3-1}+7\\a_3 = 3a_2+7\\a_3 = 3(-23)+7\\a_3 = -69+7\\a_3 = -62$

Putting n=4

$a_4 = 3a_{4-1}+7\\a_4 = 3a_3+7\\a_4 = 3(-62)+7\\a_4 = -186+7\\a_4 = -179$

Hence,

The first four terms of the sequence are: {-10,-23,-62,-179}