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PSYCHO15rus [73]

3 years ago

14

A pool measuring 8 meters by 28 meters is surrounded by a path of uniform width, as shown in the figure. If the area of the poo

l and the path combined is 476 square meters, what is the width of the path?

1 answer:

Greeley [361]3 years ago

3 0

28 because the wiishddbehehhe is wide enough

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A washer and a dryer cost 860 combined. The washer costs 90 less than the dryer. What is the cost of the dryer?

Kipish [7]

Answer:

340

Step-by-step explanation:

860 ÷ 2 = 430

430 - 90 = 340

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2 years ago

Paul has 2/3 as many postcards as shawn . the number of postcards shawn has is 3/5 of the number of postcards tim has. if the th

kakasveta [241]

P = ( 2 / 3 )s;
s = ( 3 / 5 )t ;
p + s + t = 280 ;
Then, p =( 2 / 3 )( 3 / 5 )t ;
p = ( 2 / 5 )t;
We solve the equation : ( 2 / 5 )t + ( 3 / 5 )t + t = 280 ;
( 2 / 5 )t + ( 3 / 5 )t + ( 5 / 5 )t = ( 1400 / 5 )t;
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t = 1400 ÷ 10 ;
t = 140 postcards has Tim;
p = ( 2 / 5 ) × 140 = 56 postcards has Paul;
s = ( 3 / 5 ) × 140 = 84 postcards has Shawn ;

6 0

3 years ago

PLEASE AM BEGGINNN YOUUUUU

Vikentia [17]

Answer:

Step-by-step explanation:

<em>A)</em>

<em>A - the population after its decrease </em>

<em>x - the number of years in which there has been a decrease in population</em>

<em>Hence,</em>

<em></em> $\displaystyle\\A=30000-475x\\A+475x=30000-475x+475x\\A+475x=30000\\A+475x-A=30000-A\\475x=30000-A$

<em>Divide both parts of the equation by 475:</em>

<em></em> $\displaystyle\\x=\frac{30000-A}{475}$

<em>B)</em>

<em></em> $\displaystyle\\x=\frac{30000-24300}{475} \\\\x=\frac{5700}{475}\\\\x=\frac{12*475}{475} \\\\x=12\ years$

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1 year ago

Which of the following is the midpoint between (8, 1) and (-2, -5)?

goldfiish [28.3K]

Answer:

Its c

Step-by-step explanation:

Its (8 - 2)/2 , (1-5)/2

= (3, -2)

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3 years ago

Homework counts as 10%, quizzes as 20% and tests as 70%. If the homework grade is 92, quiz grade is 68 and test grade 81 what’s

Tresset [83]

Answer:

$Final\ grade=79.5$

Step-by-step explanation:

$Homework\ grade=92\\\\quiz\ grade=68\\\\Test\ grade=81\\\\Final\ Grade=10\%\ of\ homework\ grade+20\%\ of\ quizzes\ grade+70\%\ of\ test\ grade\\\\Final\ Grade=\frac{10}{100}\times 92+\frac{20}{100}\times 68+\frac{70}{100}\times 81\\\\Final\ grade=0.1\times 92+0.2\times 68+0.7\times 81\\\\Final\ grade=9.2+13.6+56.7\\\\Final\ grade=79.5$

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2 years ago