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2 years ago

Help help help help help help help help help help help help help help help help help help help

Mathematics

2 answers:

Olenka [21]2 years ago

8 0

Answer:

im very late but 2/6

Step-by-step explanation:

snow_tiger [21]2 years ago

7 0

Answer:

2/6

Step-by-step explanation:

Since you already have 6 socks in total and you already know 4 of the color socks are either green or blue, all you would have to do is 6-4 to equal 2 and therefor making 2/6

Hope this helps :)

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Jalen charges customers a flat fee of $30 to mow their grass plus $8.50 an hour for additional yard work. If Mr. Williams pays J

Elena-2011 [213]

Answer:

She spent 2 and a half hours doing extra work.

7 0

2 years ago

What is the answer pls?

inna [77]

:) Hope this answers your question :)

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3 years ago

Which number is such that when it's ÷ 27 30 or 45 the remainder is always three

rewona [7]

Answer:

closest answer = 81

Step-by-step explanation:

81/27 = 3

81/30= 2.7

81/45 = 1.8

6 0

3 years ago

Please please please help me thanks

goldfiish [28.3K]

Answer:

1. 57 2. 81

Step-by-step explanation:

71x2=142 256-142=114/2= 57

5103/63= 81

5 0

2 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0

3 years ago