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erastova [34]
3 years ago
7

WHATS IS -5x 2/7= I NEED HELP PLEASE

Mathematics
1 answer:
Kipish [7]3 years ago
4 0

-5x 2/7 =

−10x/7

srry if it is wrong man but that is what i got

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I’ll give extra points!!
Svetach [21]
Answer:
10

Explanation:
The two shortest sides = the longest side
So I’m this case, the two shortest sides are 7 and 3, which are shown.
Then add:
7 + 3 = 10
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Rationalize the denominator √7x/75
Leokris [45]
Do what the problum ids telling you than apply it to the math and you will always get the right answer
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The value of 33 + 42 = ___.
frez [133]

Answer:

75

Step-by-step explanation:

We line up the tens place of 33 and 42 as well as the ones place so that it looks like:

33

+42

--------

Then we add first the ones, which is 3 + 2 for 5. Then we add the tens together, 3 + 4 is 7. We put the five first since its in the ones place and the 7 second since its in the tens place for 75.

6 0
3 years ago
Read 2 more answers
A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
2 years ago
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hope that helps :))
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