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klio [65]
3 years ago
13

X/3 + 1/1pls answer if you know ​

Mathematics
2 answers:
vampirchik [111]3 years ago
6 0

Answer:

\frac{x}{3} + \frac{1}{1} = \frac{x+3}{3}

Step-by-step explanation:

\frac{x}{3} + \frac{1}{1}  \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \  \ \ \ [ \  LCM \ of \ 1 , 3 = 3 \ ]\\\\= \frac{x}{3} + \frac{1 \times 3}{1 \times 3}  \\\\= \frac{x}{3} + \frac{3}{3}\\\\=\frac{x+ 3}{3} \\\\

Elenna [48]3 years ago
3 0

Answer:

<h3>\frac{x + 3}{3}</h3>

Step-by-step explanation:

<h3>\frac{x}{3}    +  \frac{1}{1} \times  \frac{3}{3}</h3><h3>\frac{x }{3}  +  \frac{3}{3}</h3><h3>\frac{x + 3}{3}</h3><h3>Hope it is helpful....</h3>
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3 0
3 years ago
Given a right triangle with legs a, b and hypotenuse c, solve for b if a= 72 and c= 75
kotykmax [81]

Answer:

The answer is a. 21.

Step-by-step explanation:

We solve this question by using Pythagoras theorem to relate the sides of a right angled triangle.

Here,

Hypotenuse of the given triangle(c)=75

Two sides of right angled triangle are:

a=72

b=?

Then,

for a given right angled triangle abc,

Using Pythagoras theorem,

c=\sqrt{a^{2} +b^{2} }

Squaring on both sides,

c^{2} =a^{2}+b^{2}

or,75^{2}=72^{2}+b^{2}

or, b^{2}=75^{2}-72^{2}

or,b^{2}=5625- 5184

or,b^{2} =441

∴b=21

So, the value of b is obtained to 21 by the use of Pythagoras theorem.

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4 years ago
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3 years ago
The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approxima
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\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\&#10;&#10; \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\&#10;&#10; \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\&#10;&#10; \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right. \\\\&#10;&#10;&#10;
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3 0
3 years ago
Read 2 more answers
Solve the system of equation by the addition method x-2y=11 and -x+6y =-31
Sonbull [250]

Answer: x = 1, y = - 5

Step-by-step explanation:

The given system of linear equations is expressed as

x - 2y = 11- - - - - - - - - - - - -1

- x + 6y = - 31- - - - - - - - - - - -2

We would eliminate x by adding equation 1 to equation 2. It becomes

- 2y + 6y = 11 - 31

4y = - 20

Dividing the the left hand side and the right hand side of the equation by 4, it becomes

4y/4 = - 20/4

y = - 5

Substituting y = - 5 into equation 1, it becomes

x - 2 × - 5 = 11

x + 10 = 11

Subtracting 10 from the left hand side and the right hand side of the equation, it becomes

x + 10 - 10 = 11 - 10

x = 1

3 0
4 years ago
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