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Vlad [161]
3 years ago
7

Solve x/42=377 using two different strategies.

Mathematics
1 answer:
Butoxors [25]3 years ago
6 0
Cross multiplying making x subject of the equation or multiplying 42 from both sides
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Answer: That's a line graph

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4 years ago
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Elizabeth lives in San Francisco and works in Mountain View. In the morning, she has 3 transportation options (take a bus, a cab
Lesechka [4]

Answer:

4/9

Step-by-step explanation:

The possibilities of transportation: (The first will be for morning, second will be for afternoon)

B, B

B, C

B, T

C, B

C, C

C, T

T, B

T, C

T, T

It is clearly seen that there are 9 transportation options.

(Using cab 1 time we have BC, CB, CT, TC. So four of the transportation methods use cab one time.)

Therefore, the probability that she will use a cab only once is 4/9.  

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3 years ago
F(6) if f(x)=4x what's the answer?<br>a.24<br>b.10<br>c.16<br>or is it d.2​
Pavlova-9 [17]

Answer:

Hi! The answer to your question is A. 24

Step-by-step explanation:

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3 years ago
There are 4 cards in the box with the numbers 2, 5, 6, and 8. Two cards are drawn one after the other. The second card drawn is
malfutka [58]

It is given that there are 4 cards with numbers 2, 5, 6, and 8.

1) It is required to list all the numbers available when two cards are drawn one after the other and the second card is placed at the right of the first card drawn.

To do this, find the sample space of the draw which are:

25,26,28,52,56,58,62,65,68,82,85,86

Hence, the required numbers.

2) Recall that probability is the ratio:

Probability=\frac{\text{ number of favorable outcomes}}{\text{ total number of possible outcomes}}

From the numbers listed, notice that the total number of possible outcomes is 12.

Since event A is "obtained number is even", notice that the number of even numbers in the listed numbers is 9 (26,28,52,56,58,62,68,82,86).

Hence, the number of favorable outcomes is 9.

Substituting into the probability ratio gives the required probability:

P(A)=\frac{9}{12}=\frac{3}{4}

Check the number of numbers that are a multiple of 5, notice that they are 3 (25,65,85).

Hence, the required probability of event B is:

P(B)=\frac{3}{12}=\frac{1}{4}

The number of multiple of 3 in the listed numbers is 0 since there is no number that is a multiple of 3.

Hence, the required probability of event C is:

P(C)=\frac{0}{12}=0

Answers:

1) {25,26,28,52,56,58,62,65,68,82,85,86}

2) P(A) = 3/4

P(B) = 1/4

P(C)= 0

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1 year ago
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noname [10]

Answer:

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Step-by-step explanation:

B or C

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