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dalvyx [7]
2 years ago
11

What do you add to 4 4/9 to make 8

Mathematics
1 answer:
Leto [7]2 years ago
4 0

You need to add 3 5/9 to make 8. If you want to know what 4 4/9 goes to, to make 8, do the opposite which is subtracting. 8 turn to 7 9/9 and then subtract 4 4/9 and then you get the answer aka 3 5/9.

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Vince's birthday party is going to be at his favorite science museum next weekend. He has 8 friends who want to see the Dinosaur
Sunny_sXe [5.5K]

Answer:

See explanation

Step-by-step explanation:

Dinosaur Discovery show = 8 friends

Wild Weather show = 4 friends

Cost of Dinosaur Discovery show = $d

Cost of Wild Weather show = $w

At regular price:

Total cost of his friends' tickets = 8 * d + 4 * w

= 8d + 4w

At half price

Total cost of his friends' tickets =

8 * 1/2d + 4 * 1/2w

= 8/2d + 4/2w

= 4d + 2w

Total cost of his friends' tickets = 4d + 2w

6 0
3 years ago
What is the factored form of 27d^6+8g^12​
likoan [24]

Answer:

The second one is the best answer to your question

7 0
3 years ago
Math question down below
marusya05 [52]
18/27 can be reduced to 2/3 so the second option should be the correct answer
5 0
3 years ago
Read 2 more answers
(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
Read 2 more answers
Can 51/54 be simplified
melisa1 [442]
We can reduce the fraction by dividing
the numerator and denominator by 3
and get our simplified answer
<span>=<span>51 ÷ 3/54 ÷ 3</span>=<span>17/<span>18
The </span></span></span>Answer:
<span>=<span>17/<span>18

</span></span></span>
3 0
3 years ago
Read 2 more answers
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