According to the temperature changes, it is found that:
- On Tuesday, the temperature at Noon was of -28.5 ºF.
- On Wednesday, the temperature at Midnight was of -5.5 ºF.
- On Thursday, the change was of -11.8 ºF.
- On Friday, the temperature at Noon was of -4.5 ºF.
<h3>What is the temperature change?</h3>
- The temperature change during a period is given by the <u>temperature at the end of the period subtracted by the temperature at the start of the period</u>.
On Tuesday:
- At the start of the period, the temperature was of -17.5 ºF.
- The change was of -11 ºF.
Hence:
On Tuesday, the temperature at Noon was of -28.5 ºF.
On Wednesday:
- At the end of the period, the temperature was of 10 ºF.
- The change was of 15.5 ºF.
Hence:
On Wednesday, the temperature at Midnight was of -5.5 ºF.
On Thursday:
- At the end of the period, the temperature was of -24 ºF.
- At the start of the period, the temperature was of -12.2 ºF.
Hence:
On Thursday, the change was of -11.8 ºF.
On Friday:
- At the start of the period, the temperature was of -21.8 ºF.
- The change was of 17.3 ºF.
Hence:
On Friday, the temperature at Noon was of -4.5 ºF.
You can learn more about change at brainly.com/question/24313700
Answer:
4 times
Step-by-step explanation:
Sample space :
6 sided cube = (1, 2, 3, 4, 5, 6)
Coin = (H, T)
Probability = required outcome / Total possible outcomes
Probability of head (H) = P(H) = 1 /2 = 0.5
Probability of 3 = P(3) = 1 /6 = 0.166666
Probability of heads and 3 on a single try = p(H) * p(3) = 0.5 * 0.166666 = 0.083333
Hence, expected number of times this is likely to occur in 48 tries :
0.083333 * 48 = 4
<2= 30 degrees since its vertical to the 4th angle.
<1=150 degrees
<3=150 degrees
since angle 3 and the 4th angle are supplementary, which means both angles equal 180 degrees, angle 3 equals 150 degrees.
since angle 3 is vertical to angle 1 it's also 150 degrees since they're congruent.
Answer:
11.18 miles
Step-by-step explanation:
The sides of a right triangle a, b, c are related by the equation
a^2 + b^2 = c^2
where c is the longest side of the triangle
Hence given that A connects B and C directly and forms a right angle at A
5^2 + 10^2 = c^2
Where c is the length of the road
25 + 100 = c^2
125 = c^2
c = 125^1/2
= 11.18 miles
(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅
