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dybincka [34]
3 years ago
13

What is the range of this data set?

Mathematics
2 answers:
Svet_ta [14]3 years ago
4 0

Answer:the answer is 15.8

Step-by-step explanation:

Vinil7 [7]3 years ago
4 0

Answer:

15.8 i had this on a math test:/

Step-by-step explanation:

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Which of the following is the correct graph of the compound inequality 4p + 1 > −7 or 6p + 3 < 33?. . A.a number line with
r-ruslan [8.4K]

We are given compound inequality 4p + 1 > −7 or 6p + 3 < 33.

Let us solve each of the inequality one by one.

4p + 1 > −7

Subtracting 1 from both sides, we get

4p + 1-1 > -7-1

4p > -8

Dividing both sides by 4, we get

p > -2.    <em>  (Shading right side for greater than sign)</em>

Solving 6p + 3 < 33.

Subtracting 3 from both sides, we get

6p + 3-3 < 33-3.

6p < 30

Dividing both sides by 6, we get

p < 5. <em> (Shading left for less than sign)</em>

<em>We have less than and greater than symbols in both inequalities, therefore we would have open circles(dots) on -2 and 5.</em>

And because we have "OR" composite inequality.

<em>So, we would take the combination of both shaded portion.</em>

<h3>Therefore, correct option is C.number line with shading everywhere.. </h3>
4 0
3 years ago
It is 10:30pm and my brain is not cooperating with me.
r-ruslan [8.4K]

Answer:

v = 180 {cm}^{3}

Step-by-step explanation:

V= <em>lwh</em><em> </em>or <em>l</em><em> </em><em>*</em><em>w</em><em>*</em><em>h</em>

<em>Length</em><em>:</em><em> </em><em>15</em>

<em>Width</em><em>:</em><em> </em><em>3</em>

<em>Height</em><em>:</em><em>4</em>

<em>V</em><em>=</em><em>15</em><em>*</em><em>3</em><em>*</em><em>4</em>

V=180

5 0
1 year ago
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Evaluate b - 2 a - c for a = -3, b = 9, and c = -6
saw5 [17]
9-2(-3)+6= 9+6+6  Your answer should be 21 if I read your question correctly



3 0
2 years ago
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I NEED A.S.A.P PLEASE I WILL GIVE BRAINLIEST
vitfil [10]

Answer:

C. 91.46

Step-by-step explanation:

Use BODMAS!

4 0
2 years ago
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For the given statement Pn, write the statements P1, Pk, and Pk+1.
Leno4ka [110]

Answer:

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

Step-by-step explanation:

We are given the statement,

P_{n} as 2 + 4 + 6 + . . . + 2n = n(n+1)

That is,

P_{n} as 2 + 4 + 6 + . . . + 2n = \sum_{i=1}^{n}2i

So, we have,

P_{1} = \sum_{i=1}^{1}2i = 2

P_{k} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k = k(k+1)

P_{k+1} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)

Thus, we get,

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

7 0
3 years ago
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