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posledela
4 years ago
15

20. If g(x) = x^3+9/3x evaluate g(-3)​

Mathematics
1 answer:
Natasha2012 [34]4 years ago
4 0

Answer:

2

Step-by-step explanation:

-3^3+9/3*-3= 2 ypu have tu substitute the x by -3 always.

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\cfrac{cos(\theta )\cdot \frac{cos(\theta )}{sin(\theta )}}{1-sin(\theta )}-1\implies \cfrac{\frac{cos^2(\theta )}{sin(\theta )}}{\frac{1-sin(\theta )}{1}}-1\implies 
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7 0
3 years ago
The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.​
vampirchik [111]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

The age of Sita = (x + 5) years.

And, the age of Gautam = x years.

Now,

5 years ago, the ratio of their ages was 3 : 2

\therefore \bf \frac{3}{2} \: = \frac{x \: + \: 5}{x}

Now by cross multiplying, we get,

3x = 2(x + 5)

3x = 2x + 10

3x - 2x = 10

<h3>x = 10 </h3>

Hence, the age of Sita = (x + 5) = (10 + 5) = 15 years.

And, the age of Gautam = x = 10 years.

Now,

The present age of Sita = 15 + 5 = 20 years. (Answer)

And, the present age of Gautam = 10 + 5 = 15 years. (Answer)

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3 years ago
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