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3 years ago

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1 answer:

Sidana [21]3 years ago

3 0

Answer:

1. It is a acute-angled triangle

2. It is a right-angled triangle

3. It is a obtuse-angled triangle

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Find the volume of a pyramid with a square base, where the perimeter of the base is

Nat2105 [25]

ANSWER:

1.9

EXPLANATION:

Volume of a pyramid = V= lwh/3

V= Volume

L= Length

W= Width

to get length we divide 5 by 4 which is 1.25

therefore V= 1.25×1.25×3.6/3

V= 1.89

1.89 to the nearest tenth is <u>1</u><u>.</u><u>9</u>

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4 years ago

Two -thirds of the children in the fourth grade class are girls. If there are 18 girls, what is the total of children in the cla

Yanka [14]

There are 27 children in the class.

18 divided by two equals 9
9 times 3 is 27

4 0

3 years ago

Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur

stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.
$P(A \cap B)$ is the probability of both A and B happening.
P(A) is the probability of A happening.

In this problem:

Event A: Three heads.
Event B: Fair coin.

The probability associated with 3 heads are:

$0.5^3 = 0.125$ out of 0.5(fair coin).
1 out of 0.5(biased).

Hence:

$P(A) = 0.125 + 0.5 = 0.625$

The probability of 3 heads and the fair coin is:

$P(A \cap B) = 0.5(0.125) = 0.0625$

Then, the conditional probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1$

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0

3 years ago

12. What percent of 60 is 12? Show your work.

Tatiana [17]

20\100 x 60=12
answer=20

7 0

3 years ago

Determine the coordinates of the vertices of the triangle to compute the area of the triangle using the distance formula (round

Karo-lina-s [1.5K]

Answer:

1. D. $50\text{ units}^2$

2. D. 45 units.

Step-by-step explanation:

We have been two graphs.

1. To find the area of our given triangle we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of base line of our triangle we will get,

$\text{Base length of triangle}=\sqrt{(15-5)^2+(5-15)^2}$

$\text{Base length of triangle}=\sqrt{(10)^2+(-10)^2}$

$\text{Base length of triangle}=\sqrt{100+100}$

$\text{Base length of triangle}=\sqrt{200}$

$\text{Base length of triangle}=10\sqrt{2}$

Now let us find the height of triangle similarly.

$\text{Height of triangle}=\sqrt{(20-15)^2+(10-5)^2}$

$\text{Height of triangle}=\sqrt{(5)^2+(5)^2}$

$\text{Height of triangle}=\sqrt{25+25}$

$\text{Height of triangle}=\sqrt{50}$

$\text{Height of triangle}=5\sqrt{2}$

$\text{Area of triangle}=\frac{\text{Base*Height}}{2}$

$\text{Area of triangle}=\frac{10\sqrt{2}*5\sqrt{2}}{2}$

$\text{Area of triangle}=\frac{50*2}{2}$

$\text{Area of triangle}=50$

Therefore, area of our given triangle is 50 square units and option D is the correct choice.

2. Using distance formula we will find the length of large side of triangle as:

$\text{Large side of rectangle}=\sqrt{(14-1)^2+(21-8)^2}$

$\text{Large side of rectangle}=\sqrt{(13)^2+(13)^2}$

$\text{Large side of rectangle}=\sqrt{169+169}$

$\text{Large side of rectangle}=\sqrt{338}$

$\text{Large side of rectangle}=13\sqrt{2}$

$\text{Small side of rectangle}=\sqrt{(4-1)^2+(5-8)^2}$

$\text{Small side of rectangle}=\sqrt{(3)^2+(-3)^2}$

$\text{Small side of rectangle}=\sqrt{9+9}$

$\text{Small side of rectangle}=\sqrt{18}$

$\text{Small side of rectangle}=3\sqrt{2}$

$\text{Perimeter of rectangle}=2(\text{Length + Width)}$

$\text{Perimeter of rectangle}=2(13\sqrt{2}+3\sqrt{2}}$

$\text{Perimeter of rectangle}=2(16\sqrt{2}}$

$\text{Perimeter of rectangle}=32\sqrt{2}$

$\text{Perimeter of rectangle}=45.2548339959390416\approx 45$

Therefore, the perimeter of our given rectangle is 45 units and option D is the correct choice.

8 0

4 years ago

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