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3 years ago

Activity

Mathematics

1 answer:

DochEvi [55]3 years ago

3 0

Answer:

My as well just put random numbers and letters in it. They can't check it on edumentum. Don't bother with the tutorials. But heres the answers for all of them.

For A

Angles A, B, and C form a triangle. The sum of the angle measurements of a triangle is 180°. So, I can find the measurement of angle C by subtracting the measurements of angle A and angle B from 180°.

For B

Angle A and angle B each measure 25°. Find the measurement of angle C by subtracting the measurements of angle A and angle B from 180°. The numerical expression for the measurement of angle C is 180° – 25° – 25°.

For C

The measurement of angle C is given by the expression 180° – 25° – 25°. So, angle C measures 130°.

For D

Angle L and angle C are supplementary angles. The sum of supplementary angles is 180°. So, I can find the measurement of angle L by subtracting the measurement of angle C from 180°.

For E

Angle C measures 130°. Find the measure of angle L by subtracting the measurement of angle C from 180°. The numerical expression for the measure of angle L is 180° – 130°.

For F

The measurement of angle L is given by the expression 180° – 130°. So, angle L measures 50°.

Step-by-step explanation:

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<h2><u>Answer with explanation:</u></h2>

Let $\mu$ be the population mean strain in a way that conveys information about precision and reliability.

The sample mean is the best point estimate of the true population mean .

As per given , we have

Sample size : n= 12

degree of freedom : $df=12-1=11$

Sample mean : $\overline{x}=25.0$

The true average strain in a way that conveys information about precision and reliability= 25.0

sample standard deviation : s= 3.3

Significance level : $\alpha= 0.05$

Since sample population standard deviation is unknown , so we use t-test.

Critical t-value for t : $t_{\alpha/2, df}=t_{0.025, 11}=2.201$

95% Confidence interval for true average strain in a way that conveys information about precision and reliability:

$\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

$25.0\pm (2.201)\dfrac{3.3}{\sqrt{12}}\\\\=\approx 25.0\pm2.10\\\\=(25.0-2.10, 25.0+2.10)=(22.9,\ 27.1)$

The 95% Confidence interval for true average strain in a way that conveys information about precision and reliability: $(22.9,\ 27.1)$

We 95% confident that the true population average strain in a way that conveys information about precision and reliability lies between 22.9 and 27.1 .

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