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3 years ago

Im sad today do you guys know why i just woke up sad

SAT

2 answers:

Alex73 [517]3 years ago

6 0

Answer:

Why you are sad?

Explanation:

Don't be sad

Zolol [24]3 years ago

5 0

maybe it's bc somebody woke u up when u didn't want to wake up or u didn't wanted to face someone but it will be alright don't be sad.

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Did you experience spending more time to make a decision that greatly affects you or your future just like anton.

fomenos

Answer:

yes

Explanation:

but I wish I knew how Anton made his own decision

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2 years ago

Asraeli has 4 dogs how many dogs does he have?

Damm [24]

Answer:

Explanation:

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3 years ago

Read 2 more answers

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len

Citrus2011 [14]

Answer:

The additional words is $2^n$

Explanation:

Given

$B(n) = 2^n$

Required

Determine the additional words; i.e. $B(n + 1) - B(n)$

From the given parameters, we have that;

B is a function of n

Such that;

$B(n) = 2^n$

To calculate $B(n+1)$ , we simply substitute n + 1 for n

$B(n) = 2^n$

$B(n + 1) = 2^{n + 1}$

Applying laws of indices

$B(n + 1) = 2^{n} * 2^1$

$B(n + 1) = 2^{n} * 2$

$B(n + 1) = 2(2^{n})$

Calculating Additional Binary Code;

$B(n + 1) - B(n)$

Substitute values for B(n + 1) and B(n)

$B(n + 1) - B(n) = 2(2^n) - 2^n$

Express $2^n$ as $2^ n * 1$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 1$

Express 1 as $2^0$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0$

Factorize

$B(n + 1) - B(n) = 2^n(2 - 2^0)$

$B(n + 1) - B(n) = 2^n(2 - 1)$

$B(n + 1) - B(n) = 2^n(1)$

$B(n + 1) - B(n) = 2^n$

Hence, the additional words is $2^n$

8 0

3 years ago

Discuss the strategy of using the part of speech of a word to determine it's meaning

kondor19780726 [428]

Answer:

School Sucks

Explanation:

Half of this stuff you will never use in your whole life, but you are still required to do it.

7 0

3 years ago

Drag the tiles to the correct boxes. Not all tiles will be used.

rewona [7]

Answer:

(-∞, -2) ∪ (-2, 6) ∪ (6, ∞)

Explanation:

The domain describes the x-values that can be used in a function.

The leftmost function contains all x-values until x = -2. This looks like (-∞,-2). Remember, open dots mean that the associated x-value is not included in the domain.

The middle function contains all x-values from x = -2 to x = 6. This looks like (-2, 6).

The rightmost function contains all x-values after x = 6. This looks like (6, ∞).

7 0

2 years ago