You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
Answer:
the angle of a quadrilateral taken in order a× 5× 4× and 2× find these angle draw a rough sketch of the quadrilateral what kind of quadrilateral is it
Answer:
When the two values are different
Step-by-step explanation:
Like in an inequality equation.
For example:

The answer would be anything greate than or equal to 30, but you would need to find x. The number line would be very useful
Hope this helps
the question is a beat confusing please make it simplify
Answer:
0.29
Step-by-step explanation:
We are given that there are 4 couples i.e. 8 people
They decide to play as teams of two and to select the teams randomly
Now we are asked How likely is it that every person will be teamed with someone other than the person he or she came to the party with
For people 1 , there are 6 options for pairing Since he or she cannot pair with his /her own partner
So, Choices For people 1 will be 6 person
So, Probability that person 1 will be teamed with someone other than the person he or she came to the party with = 
So, Probability that every person (=8 person) will be teamed with someone other than the person he or she came to the party with =
Hence Probability that every person will be teamed with someone other than the person he or she came to the party with is 0.29