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drek231 [11]
3 years ago
12

The following statistics represent weekly salaries at the Midtown Construction Company.

Mathematics
1 answer:
Sphinxa [80]3 years ago
4 0

Answer:

5

Step-by-step explanation:

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Please Help!! Screenshot below!
Reika [66]

Answer:

the answer is x+3(the 3rd option)

Step-by-step explanation:

Hope This Helps!!

(brainliest please)

7 0
3 years ago
Yolanda needs 5 pounds of ground beef to make lasagna for a family reunion. One package of ground beef holds 2 1/2 pounds. Anoth
jonny [76]
You can find the answer by adding the two packages and subtracting them by 5. 
2 1/2+2 3/5=5 1/10
5 1/10-5=1/10

Yolonda will have 1/10 left over. 
4 0
3 years ago
Solve for x: -4(3x − 2) = 6x + 2
stepladder [879]

Answer:

x = 1/3

Step-by-step explanation:

-4(3x − 2) = 6x + 2

Distribute

-12x +8 = 6x +2

Add 12x to each side

12x-12x+8 = 6x+2+12x

8 = 18x+2

Subtract 2 from each side

8-2 = 18x+2-2

6 = 18x

Divide each side by 18

6/18 = 18x/18

1/3 =x

4 0
3 years ago
Read 2 more answers
For a prosecutor to pursue a felony charge, the victim must decide to press charges.
Ymorist [56]
The answer is false because the main people like the police and judge can.
8 0
3 years ago
Read 2 more answers
The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal
Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The other parameters are given as follows:

\overline{x} = 111000, \sigma = 36730, n = 36

Hence, the lower bound of the interval is:

\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
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