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nalin [4]
3 years ago
14

What is the least common multiple of 17, 20, and 12?

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0

the least common multiple is 1,020 :)

tankabanditka [31]3 years ago
8 0

Answer:

Attached above is the answer

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lord [1]

Answer: E. :)

Step-by-step explanation:

6 0
2 years ago
The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 fe
bezimeni [28]
Assign the following variables for the origina3l rectangle:
let w = width let w + 8 = length and the area would be w(w + 8) = w² + 8w

No for the second rectangle:
let (w + 4) = width and (w + 8 - 5) or (w + 3) = length
Area = length x width or (w + 4)(w + 3) = w² + 3w + 4w + 12 using the foil method to multiply to binomials. Simplified Area = w² + 7w + 12

Now our problem says that the two area will be equal to each other, which sets up the following equation:

w² + 8w = w² + 7w + 12 subtract w² from both sides
8w = 7w + 12 subtract 7w from both sides
w = 12 this is the width of our original rectangle
recall w + 8 = length, so length of the original rectangle would be 20
7 0
3 years ago
A circle has the equation x^2+y^2+x-6y+9=0. Find the center and any x or y intercepts.
Softa [21]
We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4
5 0
3 years ago
Lynnette can wash 959595 cars in 5 days.<br> How many cars can Lynnette wash in 11 days?
aleksley [76]

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Step-by-step explanation:

Have a good day :)

6 0
3 years ago
Brian tied a 136-foot rope around the perimeter of his rectangular house. He knows that the length of the house is 10 feet less
STALIN [3.7K]

Answer:

length 42 cm and width 26 cm

Step-by-step explanation:

Given

Since Brian tied 136 foot rope around the perimeter , hence perimeter of house is 136 foot.

Given that shape of house is rectangular.

formula to calculate perimeter of rectangle can be used which is 2*(L+B)

where L is length of rectangle and B width of rectangle

Let the L and B be length of rectangular side of house

According to question

length of house is 10 feet less than twice the width of house

mathematically it can be represented as

L = 2*B - 10  --->eq. 1

Perimeter of house = 136 feet

using formula of Perimeter of rectangle

136 = 2*(L+B)

substituting the value of length in terms of width from eq. 1 in formula of perimeter

=> 136/2 = 2*B - 10 + B  (2*B+ B = 3B)

=> 68 = 3*B - 10

=> 78 = 3*B

B = 78/3 = 26

Therefore B which is width = 26 CM

length = 2*B - 10= 26*2 - 10 = 52-10=42

length of house = 42  cm

Hence dimension of Brian's house is length 42 cm and width 26 cm

5 0
3 years ago
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