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Ulleksa [173]
3 years ago
14

Please help this is for a test!

Mathematics
2 answers:
Sholpan [36]3 years ago
7 0

Answer:

5/2x4 and 2 1/2

Step-by-step explanation:

we know that,

L=bxh

= 5/2x4

it can be also 2 1/2

so, the answer is 5/2x4 and 2 1/2

please mark as brainliest

xz_007 [3.2K]3 years ago
6 0
Answer:

5/2x4 and 2 1/2
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What is the completely factored form of f(x)=x3−7x2+2x+4?
sladkih [1.3K]

Answer:

The Factored form is

f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )

Step-by-step explanation:

Given;

f(x)=x^{3} -7\times x^{2} +2x+4

To solve for x  we factorize the right side  of

f(x)=x^{3} -7\times x^{2} +2x+4

Let Substitute x for various values to check whether remainder is zero.

f(1)=1^{3} -7\times 1^{2} +2\times 1+4

Hencex-1 is a factor of the function.

Do synthetic division to find the quotient

1    1  -7  2   4

          1 -6 -4

  _____________________

      1  -6 -4 0

We get remainder 0 and quotient as,

x^{2} -(6\times x)-4

By using Quadratic Formula;

x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a}

Plug 'a' , 'b' and 'c' value from x^{2} -(6\times x)-4 equation,

x=\frac{-(-6)\pm\sqrt{-6^{2}-(4\times1\times -4 )} }{2\times1}

x=\frac{6\pm\sqrt{36+16 } }{2}

x=\frac{6\pm\sqrt{52} }{2}

x=3+\sqrt{13} and x=3-\sqrt{13}

The values of 'x' are 1 , 3+\sqrt{13} and   3-\sqrt{13}

So the Factored form is

f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )

7 0
3 years ago
Find the area of a circle in feet with the radius being 3'.
Nonamiya [84]

Answer:

28.27 ft²

Step-by-step explanation:

A=\pi r^2 where r is the radius

Plug in 3 for the radius

A=\pi (3)^2\\A=9\pi

A=28.27 (approximate answer when rounded to the nearest hundredth)

Therefore, the area of the circle is 28.27 ft².

I hope this helps!

6 0
3 years ago
Read 2 more answers
100POINTS!!!! PLEASE HELP EXPLAIN YOUR ANSWER!!! BRAINLIEST!!!
Nitella [24]

Example: Does the point (5, 2) lie within the solution set of the given system of inequalities?

y ≤ x − 5

y ≥ −x − 4

Focus on the first inequality. Does (5,2) satisfy this inequality? Is 2 ≤ 5 - 0 true? Yes, it is true. Before we call (5,2) a solution, we must determine whether or not (5,2) also satisfies the 2nd inequality: Is 2 ≥ -(5) - 4 true?

Is 2 ≥ -9? Yes! So, yes, (5,2) is a solution of this system of inequalities.

We must check out the other three possible solutions in the same fashion.


Try out the point (5,-2). Does it satisfy both inequalities?

Focusing on the first inequality: Is -2 ≤ 5 - 5 true? Yes, it is. The key question here and now is whether or not (5,-2) also satisfies y ≥ −x − 4. Is

-2 ≥ -(5) - 4 true? Is -2 ≥ -9 true? Yes. Thus, (5,-2) satisfies both inequalities and is thus another solution.

Check out (-5,2) and (-5,-2) in precisely the same way. Is either one, or are both, a solution (or solutions) to the given set of inequalities?

6 0
3 years ago
Read 2 more answers
Your construction company needs to pay a large bill for materials. You decide to pay the bill over the next few months. The bill
hram777 [196]
It would be 10,220 welcome
4 0
3 years ago
3 (a - 1) + 31 - 11a = 4 ( 2a + 3)
nikitadnepr [17]

Answer:

-⅖

Step-by-step explanation:

We need to simplify the given equation and find out the value of a , as ,

=> 3(a-1)+31-11a = 4(2a+3)

=> 3a -3+31-11a = 8a + 12

=> -8a -28 = 8a + 12

=> 16a = -28-12

=> 16a = -40

=> a = -2/5

<h3>• Hence the value of a is -⅖ .</h3>
8 0
3 years ago
Read 2 more answers
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