Please solve the question below
1 answer:
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Answer:
Option (2) and (4) are correct.
and
are points on the unit circle.
Step-by-step explanation:
Given : Some points of circles.
We have to choose which points could be points on the unit circle.
We know, the equation of circle is
..........(1)
where r is radius of circle.
We check each point for x and y values on the equation of circle and see which point gives radius = 1
Thus,
1)
Put in LHS of (1) , we have,
Simplify, we have,
Thus, is not a point on the unit circle.
2)
Put in LHS of (1) , we have,
Simplify, we have,
Thus, is a point on the unit circle.
3)
Put in LHS of (1) , we have,
Simplify, we have,
Thus, is not a point on the unit circle.
4)
Put in LHS of (1) , we have,
Simplify, we have,
Thus, is a point on the unit circle.
Thus, and
are points on the unit circle.
Answer:
5y = x + 11
Step-by-step explanation:
Given parameters:
Equation of the line ;
y = -5x + 1
Coordinates = (2, -1)
Find the equation of a line perpendicular;
Solution:
A line perpendicular to y = -5x + 1 will have slope that is a negative inverse of the given one.
Equation of a straight line is expressed as;
y = mx + c
y and x are the coordinates
m is the slope
c is the y-intercept
So, the slope of the new line perpendicular is ;
Now let us find the y-intercept of the new line;
x = -1 and y = 2
2 = x (-1) + c
c = 2 + =
The equation of the new line is;
y = x +
or multiply through by 5;
5y = x + 11