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Jlenok [28]
3 years ago
7

What is 6(4x-3)-9x solved

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0
-18 +15x = y
Spam characters: aksjakfhakdjk
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Alen is learning to scuba dive. The equation S = 26M + 20 represents the
bija089 [108]

Answer:

228 feet

Step-by-step explanation:

Since M represents the number of lessons he completes,

sub M=8 into S=26M+20

S=26(8)+20

=228

8 0
3 years ago
Marco and Drew stacked boxes on a shelf. Marco lifted 9 boxes and Drew lifted 14 boxes. The boxes that Drew lifted each weighed
JulijaS [17]
Caixa de Marcos = m
caixa de Drew = m-8
Drew levantou 14 caixas
Marcos levantou 9 caixas
D = 14(m-8)
6 0
4 years ago
Read 2 more answers
Let X equal the number of hours that a randomly selected person from City A reads the news online each day. Suppose that X has a
Nina [5.8K]

Answer:

P(Y>X) = \frac{17}{32}

Step-by-step explanation:

Recall that since X is uniformly distributed over the set [1,4] we have that the pdf of X is given by f(x) = \frac{1}{3} if 1\leq x \leq 4 and 0 otherwise. In the same manner, the pdf of Y is given by g(y) = \frac{1}{4} if 1\leq y\leq 5 and 0 otherwise.

Note that if Y is in the interval (4,5] then Y>X by default. So, in this case we have that P(Y>X| y in (4,5]) = 1. We want to calculate the probability of having Y in that interval . That is

P(Y>4) = \int_{4}^{5}\frac{1}{4}dy = \frac{1}{4}. Thus, P(Y\leq 4 ) = 1 - P(Y>4)= \frac{3}{4}.

We want to proceed as follows. Using the total probability theorem, given two events A, B we have that

P(A) = P(A|B)\cdot P(B) + P(A|B^c) \cdot P(B^c) In this case, A is the event that Y>X and B is the event that Y is in the interval (4,5].

If we assume that X and Y are independent, then we have that the joint pdf of X,Y is given by h(x,y) = f(x)g(y) = \frac{1}{12} when 1\leq x \leq 4, 1\leq y \leq 4. We can draw the region were Y>X and the function h(x,y) is different from 0. (The drawing is attached). This region is described as follows: 1\leq x \leq 4 and x\leq y \leq 4, then (the specifics of the calculations of the integrals are ommitted)

P(Y>X| y \in [1,4)) = \int_{1}^{4}\int_{x}^{4}\frac{1}{12}dy dx = \frac{1}{12}\int_{1}^{4} (4-x) dx = \frac{1}{12}\left.(4x-\frac{x}{2})\right|_{1}^{4}= \frac{1}{12}(4\cdot 4 - \frac{4^2}{2}-(4-\frac{1}{2}) = \frac{9}{2\cdot 12} = \frac{3}{8}

Thus,

P(Y>X) = 1\cdot \frac{1}{4} + \frac{3}{8}\cdot \frac{3}{4} = \frac{17}{32}

5 0
4 years ago
Find the measure of each variable
IRISSAK [1]

Answer:

m∡r = 35°

m∡t = 145°

m∡u = 35°

m∡v = 90°

m∡w = 125°

Step-by-step explanation:

m∡r = 180-(134+11)

= 180 - 145

m∡r = 35°

m∡r + m∡t = 180°

35 + t = 180

m∡t = 145°

m∡t + m∡u = 180°

145 + u = 180

m∡u = 35°

m∡u + m∡v + 55° = 180°

35 + 55 + m∡v = 180

m∡v = 90°

m∡w + 55° = 180°

m∡w  = 125°

4 0
2 years ago
A random selection of plants receiving two different types of treatments
krok68 [10]
The answer is choice D. :)
8 0
4 years ago
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