Answer:
each student will receive 14 pieces of candy and that leaves 6 pieces for himself.
14*21=294
294+6=300
Answer:
3.5 miles
Step-by-step explanation:
The straight line distance from the school to the mall is found using the Pythagorean theorem. That distance is the hypotenuse of a triangle that is 27 blocks in the east-west direction and 22 blocks in the north-south direction.
d = √(27^2 +22^2) = √1213 ≈ 34.83 . . . blocks
Since each block is 0.1 miles, the distance in miles is ...
distance to mall = (0.1 miles/block)(34.83 blocks) = 3.483 miles
Rounded to tenths, the distance from school to mall is 3.5 miles.
You have to ask yourself how would you read that decimal? It is 162 ten-thousandths because the last digit, which is 2 is in the ten-thousandths place. So the fraction would be 162/10000
Answer:
![\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given [Missing from the question]
![\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
Required

This implies that, we form a new matrix where the second row of the new matrix is a product of -3 and the second row of the previous matrix.
So, we have:
![Initial =\left[\begin{array}{cccc}1&0&1&|-1\\1&3&-1&|-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=Initial%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C1%263%26-1%26%7C-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3*1&-3*3&-3*-1&|-3*-9\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%2A1%26-3%2A3%26-3%2A-1%26%7C-3%2A-9%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)
![New =\left[\begin{array}{cccc}1&0&1&|-1\\-3&-9&3&|27\\3&2&0&|-2\end{array}\right]](https://tex.z-dn.net/?f=New%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%261%26%7C-1%5C%5C-3%26-9%263%26%7C27%5C%5C3%262%260%26%7C-2%5Cend%7Barray%7D%5Cright%5D)