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goblinko [34]
2 years ago
12

I need help please will markbrianlyest

Mathematics
1 answer:
LekaFEV [45]2 years ago
5 0
240 people will go to the food pantry
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a ski shop has a markup rate of 50% find the selling price of skis that cost the store owner $300. tell me how you got the answe
rusak2 [61]
If nthe shop has a mark up rate of 50% and they cost 300 to buy you multiply 300 by 50%  convert 50% to decimal
so you do .5*300=150
then you add 150 to 300 which means that the shop sells the skis for 450 dollars.
7 0
3 years ago
Help with #10 plz...
andrezito [222]
A. is 21.98 cm
b. is 22 cm
8 0
3 years ago
Theresa has two brothers, Paul and Steve, who are both the same height. Paul says he is
Schach [20]

Answer:

From given, we have,

Paul says he is 16 inches shorter than 1 1/2 times Theresa's height.  

Steve says he's 6 inches shorter than 1 1/3 times Theresa's height.

Let the height of Theresa be "x" inches.

So, we get,

For Paul, 1 1/2 x - 16 = T

⇒ 3/2 x - 16 = T ......(1)

For Steve, 1 1/3 x - 6 = T

⇒ 4/3 x - 6 = T .........(2)

equating  equations (1) and (2), we get,

3/2 x - 16 =  4/3 x - 6

6 - 16 = 4/3 x - 3/2 x

-10 = (8 - 9)/6 x

-60 = -x

x = 60 inches.

Therefore, Theresa is 60 inches tall.

8 0
2 years ago
Describe the end behavior of the graphed function
Troyanec [42]

You have to consider the “ends” of the x-axis, the far right (for infinitely large values of x) and left (for infinitely small values of x) of the graph.

From the diagram above you can see that:

  1. When x\rightarrow -\infty, then y=f(x)\rightarrow 1 (notice that as the values of x get smaller and smaller, the graph gets closer and closer to the line y=1);
  2. When x\rightarrow \infty, then y=f(x)\rightarrow 1. (notice that as the values of x get larger and larger, the graph gets closer and closer to the line y=1).

Answer: correct choice is D.

5 0
3 years ago
2x + y - z = -8
Andreyy89

Answer:

Multiply row 1 by \frac{1}{2}.

Step-by-step explanation:

The augmented matrix of the system of linear equation is described below:

\left[\begin{array}{cccc}2&1&-1&-8\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]

Where a_{11} = 2, if we need to create a_{11} = 1, we need to multiply row 1 by \frac{1}{2}, that is to say:

\left[\begin{array}{cccc}1&\frac{1}{2} &-\frac{1}{2} &-4\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]

Hence, the correct answer is: Multiply row 1 by \frac{1}{2}.

5 0
2 years ago
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