The solution to the given equation is p = - 1.71
To determine the solution of the given equation,
We will find the value of the variable, p, that satisfies the equation.
From the question, the given equation is
To solve this,
First, Clear the brackets
Now, Collect like terms
Now, divide both sides of the equation by 73
∴ p = - 1.71
Hence, the solution to the given equation is p = - 1.71
Learn more here: brainly.com/question/9956738
Answer:
H1 : μ < 553. Reject H1 if tcalc > –1.753.
There is not enough evidence to reject the manufacturer’s claim.
Step-by-step explanation:
We are given that the manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour.
A sample of 16 randomly chosen hours with a mean of 533 and a standard deviation of 47 is given.
Let = <u><em>average bags that an airport baggage scanning machine can handle.</em></u>
SO, Null Hypothesis, :
553 bags {means that the manufacturer’s claim is not overstated}
Alternate Hypothesis, :
< 553 bags {means that the manufacturer’s claim is overstated}
The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;
T.S. = ~
where, = sample mean = 533 bags
s = sample standard deviation = 47
n = sample of hours = 16
So, <u><em>the test statistics</em></u> = ~
= -1.702
The value of t test statistics is -1.702.
<u>Now, at 0.05 significance level the t table gives critical value of -1.753 at 15 degree of freedom for left-tailed test.</u>
Since our test statistic is more than the critical value of t as -1.702 > -1.753, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.
Therefore, we conclude that the manufacturer’s claim is not overstated and an airport baggage scanning machine can handle an average of 553 bags per hour.