A normal space<span> is a </span>topological space X<span> that satisfies </span><span>Axiom T4</span><span>: every two disjoint </span>closed sets<span> of </span>X<span> have disjoint </span>open neighborhoods<span>.</span>
The answer would be A i hope this helped
Answer:
512 ft.
Step-by-step explanation:
From the parking lot at the Red Hill Shopping Center, the angle of sight (elevation) to the top of the hill is about 25. From the base of the hill you can also sight the top but at an angle of 55. The horizontal distance between sightings is 740 feet. How high is Red Hill? Show your subproblems.
Solution:
Let x be the distance from the base of the hill to the middle of the hill perpendicular to the height, let h be the height of the hill. Therefore:
tan 25 = h/(x + 740)
h = (x + 740)tan 25 (1)
tan 55 = h / x
h = x tan 55 (2)
Hence:
(x + 740)tan 25 = xtan 55
0.4663(x + 740) = 1.428x
0.4663x + 345.07 = 1.428x
0.9617x = 345.07
x = 359 ft.
h = xtan55 = 359 tan(55) = 512 ft.
6:20=9:30=3:10=18:60=16:160/3=12:40
Step-by-step explanation:
The question requires you to find value of x in the ratios given;
Start with the first pair
6:20 = 9:x
6/20 =9/x
6x=20*9
6x=180
x=180/6=30 ⇒⇒ 6:20 = 9:30
The second pair after replacing the value of x=30 will be
9:30 = x:10
9/30=x/10
90=30x
90/30 =x
3=x⇒⇒ 9:30 = 3:10
The third pair after replacing value of x=3 will be
3:10 =x:60
3/10 =x/60
180=10x
180/10 =x
18=x ⇒⇒ 3:10 = 18:60
The fourth pair after replacing value of x=18 will be;
18:60 = 16:x
18/60 = 16/x
18x=16*60
x= (16*60)/18 =160/3
x= 160/3 ⇒⇒⇒ 18:60 = 16: 160/3
The firth pair after replacing value of x=160/3 will be;
16: 160/3 =12:x
16x= 160/3 *12
16x = 160 * 4
x= (160 *4 )/16
x=40
⇒⇒ 16: 160/3 = 12: 40
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Ratios and proportions :brainly.com/question/9512748
Keywords : ratio, value of x, proportion
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<h2>33 km</h2>
3.3cm = 0.000033km (divide by 100,000.
So, 0.000033km/yr.
0.000033 × 1,000,000
=33km
