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k0ka [10]
2 years ago
10

I got 121 but im not sure if im right​

Mathematics
1 answer:
Alexeev081 [22]2 years ago
7 0

Answer:

is 121 ........

Step-by-step explanation:

Hope this help

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Gavyn, Pip and Mark share £102 in a ratio 1:2:3. How much money does each person get?
rosijanka [135]

Answer:

see explanation

Step-by-step explanation:

sum the parts of the ratio , 1 + 2 + 3 = 6 parts

divide the amount by 6 to find the value of one part of the ratio

£102 ÷ 6 = £17 ← value of 1 part of the ratio , then

2 parts = 2 × £17 = £34

3 parts = 3 × £17 = £51

Gavyn gets £17

Pip gets £34

Mark gets £51

5 0
2 years ago
Read 2 more answers
A book sold 35400 copies in its first month of release. Suppose this represent 9.7 % of the number of copies sold to date. How m
Nata [24]

Answer:

ADDDDDDDD

Step-by-step explanation:

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2 years ago
An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

4 0
3 years ago
A writer earns 8% of total sales dollars as a commission. If 2000 copies of his book are sold at $14.95 each, how much commissio
Tasya [4]

Answer:

C $2392

Step-by-step explanation:

4 0
3 years ago
2) 3x + 4y = 4<br> -3x - 3y=-3
Alla [95]

Answer:

69

Step-by-step explanation:

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2 years ago
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