Answer:
3 <_ x
Step-by-step explanation:
multiply both sides by 15
1/5 * 15 <_ x
15/5 <_ x
3 <_ x
If A = (0,2,3,4,9,11), B = {2,3,6,8,9,10) and C= {0,2,3,9), then (A-B) n(A-C) is
timofeeve [1]
Answer:
(A-B)n(A-C) ={ }
<h3><em>hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em>.</em></h3>
<em>Wishing</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>.</em>
The numbers DO differ by 10 if they are
- 1 and 11
- 2 and 12
- 3 and 13
- 4 and 14
- 5 and 15
Each outcome technically has two ways of occurring, but since we're taking two marbles at a time, that would be the same as saying, for instance, that drawing 1 and 11 is the same as drawing 11 and 1. We only count such an event once.
So the answer is (a) 5.
Step-by-step explanation:
sec X = WX/XY = 37/12 = 3 1/12
or 3.083
Answer:
3(7 + 4)2 − 24 ÷ 6 = 62
Step-by-step explanation:
3(7 + 4)2 − 24 ÷ 6 is the given expression.
Now, by the rule of BODMAS, where B = Bracket, O= of, D = divide,
M = multiplication, A = addition and S = subtraction
we try and solve the following expression in the same order.
Solving the bracket first, we get
3<u>(7 + 4)</u>2 − 24 ÷ 6 = 3(<u>11</u>)2 − 24 ÷ 6 =<u> 66</u> − 24 ÷ 6
Next, we solve divide,
66 − <u>24 ÷ 6</u> = 66 - <u>4</u>
Next, solving the subtraction, 66 - 4 = 62
Hence, 3(7 + 4)2 − 24 ÷ 6 = 62
