the answer is on the picture with solving
The coordinate of point Y such that the ratio of MY to YJ is 2:3 is 6.4
<h3>How to determine the point?</h3>
The complete question is added as an attachment
The coordinates are given as:
M = 2
J = 18
The ratio is given as:
Ratio = 2 : 3
The location of the point Y is then calculated as:
Y = Ratio * (J - M)
This gives
Y = 2/(2 + 3) * (18 - 2)
Evaluate
Y = 2/5 * 16
This gives
Y = 6.4
Hence, the coordinate of point Y such that the ratio of MY to YJ is 2:3 is 6.4
Read more about line segment ratio at:
brainly.com/question/12959377
#SPJ1
<span>If M is the midpoint of CD, CM = 2x+3 and MD = 3x-6, then:
MD = CM
3x - 6 = </span>2x + 3
3x - 2x = 3 + 6
x = 9
CM = 2x+3 = 2*9+3 18+3 = 21
MD = CM = 21
CD = CM + MD = 21 + 21 = 42
Answer:
D) arccsc (x) = arcsin (1/x)
Step-by-step explanation:
Here's how you can prove it: Consider a right triangle with hypotenuse 1 and a side length 1/x. If θ is the angle opposite of 1/x, then:
sin θ = 1/x
and
csc θ = x
Solving for θ:
θ = arcsin (1/x)
θ = arccsc (x)
Therefore:
arccsc (x) = arcsin (1/x)
Answer:
2/3
Step-by-step explanation:
Subtract 2 2/3 from 3 1/3 to determine how much flour she'll have left over.

2/3 of flour is left over after making one batch of brownies.