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Kisachek [45]
3 years ago
15

Substitution 1.y=-5x-19 y=-6x-24 2.y=-6x-22 y=-3x-10

Mathematics
1 answer:
omeli [17]3 years ago
5 0

Answer:

1. y=5 and x=-5

2. y=2 and x=-4

Step-by-step explanation:

1.y=-5x-19

y=-6x-24

since both equations are equal to y, they are also equal to eachother

-5x-19=-6x-24

addition P.O.E.

x-19=-24

addition P.O.E.

x=-5

substitute x into one equation

y=-5*-5-19

y=6

2. y=-6x-22

y=-3x-10

since both equations are equal to y, they are also equal to eachother

-6x-22=-3x-10

addition P.O.E.

-22=3x-10

addition P.O.E.

-12=3x

division P.O.E.

-4=x

substitute x into one equation

y=-3*-4-10

y=2

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Bill brought 8 shirts, 6 pairs of shorts and 3 pairs of shoes to camp. How many different outfits consisting of a shirt, a pair
Ilya [14]
144 outfits, I believe.

8 X 6 X 3= 144
3 0
3 years ago
Jay works as a waiter at a restaurant.
ryzh [129]

Answer:

67.33.

Step-by-step explanation:

To figure out the tip, you need to find 20% of $52.60.

0.2×52.6=10.52

You should leave $10.52 for the waiter if you want to leave him exactly 20%.

To figure the tax, you need to find 8% of $52.60.

0.08×52.6=4.208

Next, add them up:

52.6+10.52+4.208=67.328

The total bill, including tax and tip, will be $67.33.

7 0
2 years ago
The average age of staff in the maths department is 40.
pashok25 [27]

Answer:

Cerian is 28 years old

Step-by-step explanation:

The given parameters are;

The average age of the staffs in the mathematics department = 40

The number of staffs in the department = 7

The average age of Jill, Nicky and Wendy = 41

The average age of Andy, Alan and Cathy = 43

From the given parameters, we have;

The average age of the staffs in the mathematics department = (The sum total of the ages of the members of the math department)/(The number of staffs in the department)

Therefore;

40 = (The sum total of the ages of the members of the math department)/ (7)

From which we have;

The sum total of the ages of the members of the math department = 40 × 7 = 280

Which gives;

Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age = 280 years

The average age of Jill, Nicky and Wendy = 41

Given that Jill, Nicky, and Wendy make up 3 of the 7 members of staffs, we have;

The average age of Jill, Nicky and Wendy = (The sum total of the ages of Jill, Nicky, and Wendy)/(The number of staff Jill, Nicky, and Wendt make)

Therefore;

The sum total of the ages of Jill, Nicky, and Wendy = 41 × 3 = 123

Which gives;

Jill's age + Nicky's age + Wendy's age = 123 years

Similarly, the sum total of the ages of Andy, Alan, and Cathy = 43 × 3 = 129

Which gives;

Andy's age + Alan's age + Cathy's age = 129 years

Therefore;

Cerian's age = (Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age) - (Jill's age + Nicky's age + Wendy's age) + (Andy's age + Alan's age + Cathy's age)

∴ Cerian's age = 280 years - 123 years - 129 years = 28 years

6 0
3 years ago
Question. 1 :
vovikov84 [41]
<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

4 0
2 years ago
What is the measure of each angle in any equilateral triangle?
miskamm [114]
60°; all of of the angles of a triangle add up to 180° so 180 divided by 3 equals 60°.
3 0
3 years ago
Read 2 more answers
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