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WARRIOR [948]
3 years ago
5

Write an expression that simplifies to x to the power of -4

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
8 0

Answer:

x⁻⁴ would be written as \frac{1}{x^{4} } as it's simplified form

Hope this helps!

KonstantinChe [14]3 years ago
4 0

Answer:

1/x⁴

Step-by-step explanation:

We need to simplify the expression , x -⁴ .

  • We know that , if a number has negative power, then in order to convert , the negative power into positive , we will inverse ( reciprocal) and then put the positive power.

=> x -⁴

=> (1/x) ⁴

=> 1⁴/ x ⁴

=> 1/x⁴

<h3><u>Hence</u><u> the</u><u> </u><u>required</u><u> answer</u><u> </u><u>is </u><u>1</u><u>/</u><u>x</u><u>⁴</u><u> </u><u>.</u></h3>
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Explain what percent of a dollar a quarter, 2 nickels, a dime and 3 pennies are.
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48%
quarter=25%
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dime=10%
3 pennies=3%
25+10+10+3=48
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4 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPP PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
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Answer:

1) 10

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Step-by-step explanation:

4 0
3 years ago
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We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely. (a) Given that the roll results
boyakko [2]

Answer:

a) \frac{1}{7}

b) \frac{2}{15}

Step-by-step explanation:

Given : We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely.

The outcomes are :

(1, 1) (1, 2)  (1, 3)  (1, 4)  (1, 5)  (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(a) Given that the roll results in a sum of 3 or more, find the conditional probability that doubles (the first and the second rolls result in the same number) are rolled.

Let P(A) be the probability of event that the roll results in a sum of 3 or more.

Except (1,1) rest sum is 3 or greater than 3.

So, P(A)=\frac{35}{36}

Now, P(A and B) is that the roll results in a sum of 3 or more and that doubles (the first and the second rolls result in the same number) are rolled.

i.e. (2,2), (3,3), (4,4), (5,5), (6,6) - 5

P(A\cap B)=\frac{5}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{5}{36}}{\frac{35}{36}}

P(B|A)=\frac{5}{35}

P(B|A)=\frac{1}{7}

(b) Given that the two dice land on different numbers, find the conditional probability that the sum is 5.

Let P(A) be the probability of event that two dice land on different numbers.

Except (1,1),(2,2), (3,3), (4,4), (5,5), (6,6) rest two dice land on different numbers.

So, P(A)=\frac{30}{36}

Now, P(A and B) is that two dice land on different numbers and the sum is 5.

i.e. (1,4), (2,3), (3,2), (4,1) - 4

P(A\cap B)=\frac{4}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{4}{36}}{\frac{30}{36}}

P(B|A)=\frac{4}{30}

P(B|A)=\frac{2}{15}

4 0
3 years ago
X-11/2x+10÷x^2-8×-33/x+5​
Temka [501]

Answer:

Step-by-step explanation:

SOLVE FOR X

x=  

2

13

​  

−3

​  

≈0.302775638

x=  

2

−  

13

​  −3

≈−3.302775638

Hope this helps xxx

6 0
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