Step-by-step explanation:
1 Simplify 8\times -48×−4 to -32−32.
10\times -32
10×−32
2 Simplify.
-320
−320
There are 4! = 24 poosible permutations of the four letters. Let the letters be A, B, C and D. Two permutations will have only letter A in the correct envelope, two more permutations will have only letter B in the correct envelope, two more will have only letter C in the correct envelope and two more will have only letter D in the correct envelope. Therefore 8 out of the 24 possible permutations will have only one letter with the correct address. The required probability is 8/24 = 1/3.
Answer:
8
Step-by-step explanation:
16x13=208
208÷26=8
8 bags of fertilizer
Answer:
$6.22
Step-by-step explanation:
Given;
Total number of coins N = 50
Number of pennies p = 14% of N = 0.14 × 50 = 7
Number of dimes d = 32% of N = 0.32×50 = 16
Number of nickels n = 4 + number of pennies = 4+p
n = 4+7 = 11
Number of quarters q;
N = p+d+n+q
q = N - (p+d+n)
q = 50-(7+16+11)
q = 16
1 Penny = 1 cent = $0.01
1 Nickel = 5 cent = $0.05
1 dime = 10 cents = $0.10
1 quarter = 25 cents = $0.25
Total amount in the bag is;
C = 0.01p + 0.05n + 0.10d +0.25q
Substituting the values;
C = 0.01(7) + 0.05(11) + 0.10(16) + 0.25(16)
C = $6.22
The bag contains $6.22
