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2 years ago

9

Write the equation of a line that goes through the point (5, -6) and is parallel to the line y = 2x + 7.

1 answer:

lilavasa [31]2 years ago

3 0

Parallel = same slope
y - y1 = m( x - x1)
Solution: y + 6 = 2(x - 5)

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Solve 2x+2>10 i need to know what this is?

mrs_skeptik [129]

Answer:

x>4

Step-by-step explanation:

$2x + 2 > 10 \\ 2x > 10 - 2 \\ 2x > 8 \\ x > 4$

Sorry if there is any mistakes

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3 years ago

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3 years ago

Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)

Elis [28]

Answer:

Distance between point $(3,4)$ and midpoint of line joining $(8,10)$ and $(4,6)$ = $5$ units.

Step-by-step explanation:

Given:

Points:

$A(3,4)\\B(8,10)\\C(4,6)$

To find distance from point A to midpoint of BC.

Midpoint M of BC:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\$

$M=(\frac{8+4}{2},\frac{10+6}{2})\\$ [Plugging in points $B(8,10)\ and\ C(4,6)$ ]

$M=(\frac{12}{2},\frac{16}{2})\\$

$M=(6,8)\\$

Distance between A and M:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

$D=\sqrt{(6-3)^2+(8-4)^2} \\$ [Plugging in points $A(3,4)\ and\ M(6,8)$ ]

$D=\sqrt{(3)^2+(4)^2} \\$

$D=\sqrt{9+16} \\$

$D=\sqrt{25} \\$

$D=\pm5$

Since distance is always positive ∴ $D= 5$ units

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3 years ago

Graph the given relation or equation and find the domain and range. Then

vredina [299]

X=1 Hopefully that helped

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3 years ago

Factor completely 5ab + 3ay + 5b + 3y. (5b + 3y)(a + 1) (5b − 3y)(a + 1) (5b + 3y)(a − 1) Prime

Katen [24]

<span>5ab + 3ay + 5b + 3y
a(5b + 3y) + 1(5b + 3y)
(a+1)(5b + 3y)
(5b + 3y)(a+1)</span>

7 0

3 years ago

Read 2 more answers