You can eat me,im green and round what am i

What is an example of a scope three carbon emission brainly.

Sati [7]

An example of a scope three carbon emission is; driving a gasoline-fueled vehicle

<h3>What is Scope three carbon emission?</h3>

Scope 3 emissions are a defined as the consequence of the activities of the company that occur from sources not owned or controlled by the company.

Some examples of scope 3 carbon emission activities are;

Extraction and production of purchased materials.

Transportation of purchased fuels.

Use of products and services.

Thus, when applied in practical, we can say that an example of a scope three carbon emission is; driving a gasoline-fueled vehicle

Read more about carbon emissions at; brainly.com/question/1301348

#SPJ1

7 0

2 years ago

Robin hood wishes to split an arrow already in the bull's-eye of a target 40 m away.

Ira Lisetskai [31]

Answer:

v = 38 m/s d = 40 m time taken

Explanation:

5 0

2 years ago

Its pretty hard what can I do to get help

omeli [17]

Hmm What do you mean?

6 0

4 years ago

A piece of land was purchased for $65,000. The value of the land has slowly been decreasing by 1% annually. How much will the la

Dennis_Churaev [7]

Então em 20 anos a terra valeria R$13000

1%de 65000 é 650

650x20= 13000

6 0

3 years ago

If the aluminum block is initially at 25 ∘c , what is the final temperature of the block after the evaporation of the alcohol? a

Bumek [7]

The temperature of an object is how cold or hot it is.

The final temperature is 12.3 degrees Celsius

<h3>How to determine the final temperature </h3>

The given parameters are:

$\Delta H_{vap} = 45.4\ kJ/mol$ --- the heat of vaporization

$C_p = 0.903J/g^oC$ --- the specific heat of Aluminum

$m = 1.12g$ --- the mass of alcohol

$M = 60.1g/mol$ -- the molecular mass of alcohol

Start by calculating the moles of alcohol using:

$Moles = \frac{Mass}{Molecular\ Weight}$

So, we have:

$n = \frac{1.12g}{60.1g/mol}$

$n= 0.0186\ mol$

Next, calculate the amount of heat absorbed by the alcohol using:

$n * \Delta H_{vap} = -m_{alcohol}* C_p * \Delta T$

The mass of alcohol is 73 grams. So, we have:

$0.0186 * 45.4 = -73* 0.903 * \Delta T$

Evaluate the products

$0.84 = -65.92* \Delta T$

Divide both sides by -65.92

$\Delta T = -0.0127$

Express as degrees Celsius

$\Delta T = -12.7$

Also, we have:

$\Delta T = T_i - T_f$ --- the difference in the initial and the final temperatures.

This gives

$-12.7 = T_f - 25$

Collect like terms

$T_f = 25 - 12.7$

$T_f = 12.3$

Hence, the final temperature is 12.3 degrees Celsius