Wich equation best represent the relation ship between x and y plz answer

The Ship It Anywhere Company bought a truck for $245,000. According to the company’s accounting department, the truck will depre

Svetradugi [14.3K]

Answer:

1. $V(t) = -32500t + 245000$

a. The slope of the function is m = -32500, and it means the change in the value of V(t) for each unitary change in the value of t.

b. The V-intercept is b = 245000, and it means the value of V(t) when t = 0, that is, the inicial value of V(t).

c. The formula is: $V(t) = -32500t + 245000$

2. t-intercept: $t = 7.5385$

The t-intercept means when the function V(t) will be zero, that is, the truck has no value anymore.

3. Graph in the image attached.

4. The domain is t = [0, 7.5385] and the range is V(t) = [245000, 0].

5. $V(8) = -15000$

It means the price the truck will have after 8 years. It does not make sense, because the truck can't have a negative price.

6. After 3.6 years.

7. Between 3.23 years and 5.63 years.

Step-by-step explanation:

1.

The inicial value is 245,000, and each year the value decreases 32,500, so we can write the equation:

$V(t) = -32500t + 245000$

a. The slope of the function is m = -32500, and it means the change in the value of V(t) for each unitary change in the value of t.

b. The V-intercept is b = 245000, and it means the value of V(t) when t = 0, that is, the inicial value of V(t).

c. The formula is: $V(t) = -32500t + 245000$

2.

To find the t-intercept we just need to use V(t) = 0 and then find the value of t:

$0 = -32500t + 245000$

$32500t = 245000$

$t = 7.5385$

The t-intercept means when the function V(t) will be zero, that is, the truck has no value anymore.

3.

The graph of the function is in the image attached.

4.

The domain is t = [0, 7.5385] and the range is V(t) = [245000, 0].

5.

$V(8) = -32500*8 + 245000 = -15000$

It means the price the truck will have after 8 years. It does not make sense, because the truck can't have a negative price.

6.

$128000 = -32500t + 245000$

$32500t = 117000$

$t = 3.6$

After 3.6 years.

7.

$62000 = -32500t + 245000$

$32500t = 183000$

$t = 5.6308$

$140000 = -32500t + 245000$

$32500t = 105000$

$t = 3.2308$

Between 3.23 years and 5.63 years.

5 0

3 years ago

-2(6) + 3(5 – 4· 2)

rjkz [21]

Answer:

-21

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Joe bought 15 items for $135. If the 15 items consisted of notebooks that cost $4.50 each and calculators that cost $12.00 each,

Luda [366]

n + c = 15

4.5n + 12c = 135

c = 15 - n

12c = 180 - 12n

180 - 12n + 4.5n = 135

-7.5n = - 45

15n = 90

notebook = 6

6 + c = 15

calculator = 9

6 0

2 years ago

Please help me with my math homework

Dafna11 [192]

Hi there!

$\large\boxed{UV = 13}$

Since U and V are midpoints of the legs, then UV is the average of both WX and ZY.

Therefore:

(ZY + WX)/2 = UV

Substitute in the given expressions:

[(6x + 5) + (x + 7)]/2 = 8x - 3

Simplify by combining like terms:

(7x + 12)/2 = 8x - 3

Multiply both sides by 2:

7x + 12 = 16x - 6

Subtract 7x from both sides and add 6 to both sides:

18 = 9x

Divide both sides by 9:

18/9 = x

x = 2.

Plug in this value of x into the equation for UV:

8(2) - 3 = 16 - 3 = 13.

8 0

3 years ago

A certain model of automobile has its gas mileage (in miles per gallon, or mpg) normally distributed, with a mean of 28 mpg and

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

We are finding the probability, which is a percentage, of each of these intervals on our standard bell curve. In order to find this percentage, we need to find the z-score that provides this percentage. To find the z-score:

$z=\frac{x_i-\bar{x}}{\sigma}$ which is the number in question minus the mean, all divided by the standard deviation. We're first looking for the probability that the gas mileage on a certain model of car is less than 26 mpg.

To find this z-score:

$z=\frac{26-28}{4}=-.5$ Depending upon which table you look at for the z-score determines how you will find it. The z-score that measure from the value and to the left of it is what we need. This decimal is .3085375, or 30.8538%.

Onto b., which is for the percentage of cars that have gas mileage over 34 mpg. Find the z-score, and this time, we look to the right of the value for the percentage:

$z=\frac{34-28}{4}=1.5$ and to the right of 1.5 standard deviations we will find .0668072, or 6.68072%

Then finally c., which wants the probability that the gas mileage on one of these cars is greater than 22 but less than 34 mpg. To do this we have to find the z-scores of each and then do some subtracting. First the z-scores:

$z=\frac{22-28}{4}=-1.5$ The percentage of data that lies to the right of that z-score is .9331927

The z-score for the other value, 34, was already found as 1.5, having .0668072 of the data to the right of that z-score. We subtract the smaller from the larger to determine what's left in-between:

.9331972 - .0668072 = .86639, or as a percentage, 86.639% of the cars fall into this interval for gas mileage.

7 0

3 years ago