(1/8), (2/8), (3/8), (4/8), (5/8), (6/8), (7/8)
if u want, 2/8=1/4, 4/8=1/2, 6/8=3/4
I dont know how to delete a answer and i got it wrong apparently so sorry
Given:
The coordinates of point K' are (6,5).
K' is the image of K after a reflection in the line y=2.
To find:
The coordinates of point K.
Solution:
Let the coordinates of point K are (a,b).
If a figure is reflected over the line y=2, then
Using this formula, the coordinates of image of K are
The coordinates of point K' are (6,5).
On comparing both sides, we get
Therefore, the coordinates of point K are (6,-1).
Answer:
-13/84
Step-by-step explanation:
Calculation to Find the exact value of the trigonometric expression
First step is to find tan(u)
Based on the information given we were told that sin(u) = -3/5 which means if will have -3/5 in the 4th quadrant would have triangle 3-4-5
Hence:
tan(u)=-3/4
Second step is to calculate tan(v)
In a situation where cos(v) is 15/17 which means that we would have triangle 8-15-17
Hence:
tan(v) = 8/15
Now Find the exact value of the trigonometric expression using this formula
tan(u+v) = (tan(u) + tan(v))/(1-tan(u)tan(v)
Where,
tan(u)=-3/4
tan(v)=8/15
Let plug in the formula
tan(u+v)=(-3/4)+(8/15)÷[1-(-3/4)(8/15]
tan(u+v)=(-45+32)÷(60-24)
tan(u+v)=-13/84
Therefore exact value of the trigonometric expression will be -13/84
