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2 years ago

The function f (t) = 12(1 +0.03) can be used to determine the population, in thousands of a town t years

Mathematics

1 answer:

Alja [10]2 years ago

5 0

f= the original amount of people, a steady growth throughout the years

t=time

In 1955 the population was 12 thousand. Compared to the current population of 12.36 thousand, the population then was roughly 77%.

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Skylar owns a trucking company. For every truck that goes out, Skylar must pay the driver $11 per hour of driving and also has a

jeyben [28]

Answer:

The set of needed equations is

h = 30 m

11 m + 3 h = 909 where

the driver drove for m hours.

h : distance covered in m hours

Step-by-step explanation:

Here, according to the question:

The per hour rate of driver = $11

The gas maintenance expense = $3 per mile.

The total distance covered by drives is 30 miles per hour.

The total expenses paid to driver = $909

Now, let us assume the driver drove for m hours.

The average speed of driver was 30 miles / hour

⇒ Driver covers 30 miles in 1 hour

SO, distance covered in m hours = h = m x 30 = 30 m

or, h = 30 m

So,according to the question, the total amount paid :

Charges of m hours driving + maintenance charges for h miles

= 11 m + 3( h)

or, 11 m + 3 h = $909

Hence the set of needed equations is

h = 30 m

11 m + 3 h = 909

4 0

3 years ago

Please help

svp [43]

Answer:

(x + 2)^2 + (y + 2)^2 = 16

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Assume the exponential growth model A(t)equals=Upper A 0 e Superscript ktA0ekt and a world population of 5.95.9 billion in 2006

Whitepunk [10]

Answer:

1.4% is the maximum acceptable annual rate of growth such that the population must stay below 24 billion during the next 100 years.

Step-by-step explanation:

We are given the following in the question:

The exponential growth model is given by:

$A(t) = A_0e^{kt}$

where k is the growth rate, t is time in years and $A_0$ is constant.

The world population is 5.9 billion in 2006.

Thus, t = 0 for 2006

$A_0 = 5.9\text{ billions}$

We have to find the maximum acceptable annual rate of growth such that the population must stay below 24 billion during the next 100 years.

Putting these values in the growth model, we have,

$24 = 5.9e^{100k}\\\\k = \dfrac{1}{100}\ln \bigg(\dfrac{24}{5.9}\bigg)\\\\k = 0.01403\\k = 0.01403\times 100\% = 1.4\%$

1.4% is the maximum acceptable annual rate of growth such that the population must stay below 24 billion during the next 100 years.

8 0

2 years ago

6. Would the amount of dissolved oxygen in the Missouri River increase or decrease if large amounts of chemical waste were dumpe

WARRIOR [948]

<span>The amount of dissolved oxygen in the Missouri River would decrease if large amounts of chemical waste were dumped into it. It would decrease because the chemical waste would feed on the microorganisms and reduce the amount of oxygen in the river.</span>

7 0

3 years ago

I know the unit rate but don’t know the label.

guajiro [1.7K]

Miles per minute or miles per hour depending on how you did it.

7 0

3 years ago