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nata0808 [166]
3 years ago
12

Age of Yusuf is 24 years more than half the age of Ajay. 5 years before sum of their ages was 41. Find their present ages.​

Spanish
1 answer:
Luda [366]3 years ago
7 0

Ajay's age = 18 years

Yusaf's age =  33 years

As shown in the question above, Yusuf is 24 years older than half Ajay's age. Therefore, we can represent Yusuf's age, mathematically, as follows: (1x / 2 + 24)

Since we don't have information about Ajay's age, we can represent her as x years.

In addition, the question shows us that, five years ago, the sum of their age was 41. In this way, we must represent the age of both of them in the following way:

Yusuf's Age: 1x / 2 + (24 - 5) ------> 1x / 2 + 19

Ajay's Age: x - 5

Now we can put these two expressions together by adding their age to five years ago. This will be done as follows:

  • (x - 5) + (1x/2 + 19) = 41
  • 3x/2 + 14 = 41 (Numbers accompanied by letters were added to each other and numbers not accompanied by letters were added to each other.)
  • 3x/2 = 41 - 14 (numbers accompanied by letters that are in front of the sign "=" must be passed to the other side, with the sign changed.
  • 3x/2 = 27
  • x = 27 × 2/3
  • x = 18

As we saw above, the letter "X" represents Ajay's age, so Ajay is 18 years old.

Now we can substitute that result into the equation representing Yusuf's age. Thus, the "x" in the equation will be replaced by the number "18," as follows:

1x / 2 + 24 =

1 × 18/2 + 24 =

9 + 24 = 33 years.

Yusuf's age is 33 years old.

We can prove this by subtracting 5 years from their age and adding them up to see if the result equals 41.

33-5 = 28

18-5 = 13

28 + 13 = 41

You can get more information in the following related questions:

https://brainly.in/question/44055896

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