All categories

3 years ago

What is the answer to −5/12−3/10

Mathematics

1 answer:

Musya8 [376]3 years ago

8 0

Answer:

The answer is -0.71666666666 in decimal form.

In fraction form it is -43/60.

Step-by-step explanation:

You might be interested in

Factor this trinomial.

Ahat [919]

$x^2+2x-3=(x+3)(x-1)$

4 0

4 years ago

Who got home first.

Murljashka [212]

Francesca got home first because If you round 13/15 you get 1 whole.
"AB84"
Plagarism Checker-<span>https://smallseotools.com/plagiarism-checker/</span>

7 0

4 years ago

Find an expression which represents the difference when (-5x-y) is subtracted from (9x+2y) in simplest terms.

AnnyKZ [126]

Answer:

4x+y add like terms ... -5+9=4 and -y(or -1)+2y=y

4 0

2 years ago

An exponential distribution is formed by the waiting times for a patient in the emergency room. The average waiting time for thi

lapo4ka [179]

Answer:

0.207 = 20.7% probability that the wait time will be more than an additional 41 minutes

Step-by-step explanation:

To solve this question, we should understand the exponential distribution and conditional probability.

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

The average waiting time for this distribution is 38 minutes.

This means that $m = 38, \mu = \frac{1}{38} = 0.0263$

Given that it has already taken 37 minutes, what is the probability that the wait time will be more than an additional 41 minutes?

Event A: Taking more than 37 minutes.

Event B: More than 37 + 41 = 78 minutes.

Probability of taking more than 37 minutes:

$P(A) = P(X \leq 37) = 1 - e^{-0.0263*37} = 0.6221$

More than 37 minutes and more than 78 minutes:

The intersection is more than 78 minutes, so:

$P(A \cap B) = P(X > 78) = e^{-0.0263*78} = 0.1286$

The probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1286}{0.6221} = 0.207$

0.207 = 20.7% probability that the wait time will be more than an additional 41 minutes

3 0

3 years ago

PLZ HELP 10 POINTS FOR THIS QUESTION PLZ PLZ

Nookie1986 [14]

Answer:

Tried my best..... Hope it helps! :)

5 0

3 years ago