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2 years ago

4−32⋅(−0.25)−12÷13, what's the answer?

Mathematics

2 answers:

vampirchik [111]2 years ago

8 0

The answer is 144 over 13

Nata [24]2 years ago

7 0

144/33 is da anwser kkkk

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Always, sometimes, or never.

irinina [24]

The ratio is always 1:1:√2

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2 years ago

In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years. Assuming that life expectancy bet

Darya [45]

Answer:

49145 years

Step-by-step explanation:

In a certain country the life expectancy for women in 1990 was 45 and in 2000 it was 85?years.

Assuming that life expectancy between 2000 and 2100 increases by the same percentage as it did between 1900 and 2000,what will life expectancy be for women in 2100?

In 10 years, the expectancy increased by 85/45 = 17/9

between 2000 and 2100, it will increas by 10 time 10 years, so expected expectancy is $85*(\frac{85}{45})^{10} = 49145$ years

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2 years ago

Identify this pair of angles

REY [17]

They are opposite exterior angles

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2 years ago

Need help, will mark brainliest plus 50 points.

uranmaximum [27]

Answer:

Step-by-step explanation:

To write the inequality, we need to first caculate the amount of money that Lia would ACTUALLY earn each week and compare that to her goal of $600.

We cannot actually get the amount of money that Lia would get because we don't know her sales so we will represent the sales with a X.

450+ X(5%). -This the amount of money she would egt from her sales. We need to also figure out 5% of 450 to solve the next part of the equation. That is $22.5. 600-450=150/22.5= 6.6666- which is about 7 sales.

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3 years ago

Find the area of the surface. the part of the hyperbolic paraboloid z = y2 â x2 that lies between the cylinders x2 + y2 = 4 and

lukranit [14]

$x=u\cos v,y=u\sin v\implies z=u^2\sin^2v-u^2\cos^2v=-u\cos2v$

$\mathbf s(u,v)=\langle u\cos v,u\sin v,-u\cos2v\rangle$

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

$\displaystyle\iint_{\mathcal S}\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=2}^{u=5}u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv=\dfrac{(101^{3/2}-17^{3/2})\pi}6$

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2 years ago