2. Caveman Sampson chases a saber tooth tiger at an average speed of 3 miles per hour. The tiger runs at an average speed of 5 m
1 answer:
9514 1404 393
Answer:
D. 4 hours
Step-by-step explanation:
The tiger will run (5 mi/h)(2 h) = 10 mi in 2 hours. That will put it 2+10 = 12 miles from Sampson's starting location.
Samson can run 12 miles in time ...
time = distance/speed = (12 mi)/(3 mi/h) = 4 h
Sampson will get to the tiger's location after 4 hours, just as the tiger is ending its rest period.
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The graph shows the position of Sampson (red) and the tiger (blue) x hours after the chase starts. The distance (y miles) is measured from Sampson's starting point, assuming the tiger is running away.
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so
whatever "x" and "y" amounts are, we know, they must add up to 160 pints
thus x + y = 160
now, whatever the concentrated amount of solute in the mixture, we know they must add up to 160*0.85 or 136
thus 0.7x + 0.95y = 136
thus
solve for "x", to see how much of the 70% pure juice will be needed
what about "y"? well, y = 160 - x