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3 years ago

DISCLAIMER: THERE ARE MANY QUESTIONS LIKE THIS ONE, SO MAKE SURE THAT YOU ARE ANSWERING THIS SPECIFIC QUESTION.

Mathematics

1 answer:

lakkis [162]3 years ago

7 0

Answer:

A. 71% (±18%)

Step-by-step explanation:

Based on the confidence interval relation :

Mean ± Margin of error

The mean could be any given value :

However, the margin of error at a given confis nce level will will affected by the sample size, larger sample sizes will result in smaller margin of error values as the it will result in a large value denominator hence giving a small margin if error value when divided.

Margin of Error = Zcritical * σ/√n

Since.weve been told that the sample size is small, this will result in a large error margin value, from the options given, the value with the largest error margin value will be produced by the smallest samole size. Hence the option with the largest error margin value is ; ±18%

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Use the Law of Cosines to find the values of x and y. (PLEASE HELPPP!!!!)

vredina [299]

Answer:

$x = 49.8^\circ\\y = 54.6^\circ$

Step-by-step explanation:

Kindly refer to the image attached in the answer region for labeling of triangle.

AB = 16

BC = 19

AC = 15

$\angle ABC = x^\circ\\\angle ACB = y^\circ$

We have to find the angles x and y i.e. $\angle B \text{ and }\angle C$ .

Formula for cosine rule:

$cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}$

Where

a is the side opposite to $\angle A$ ,

b is the side opposite to $\angle B$ and

c is the side opposite to $\angle C$ .

$\Rightarrow cos x = \dfrac{19^{2}+16^{2}-15^{2}}{2 \times 19 \times 16}\\\Rightarrow cos x = \dfrac{392}{608} \\\Rightarrow x = 49.8^\circ$

Similarly, for finding the value of y:

$cos C = \dfrac{a^{2}+b^{2}-c^{2}}{2ab}\\\Rightarrow cos y = \dfrac{19^{2}+15^{2}-16^{2}}{2 \times 19 \times 15}\\\Rightarrow cos y = \dfrac{330}{570}\\\Rightarrow y = 54.6^\circ$

Hence, the values are:

$x = 49.8^\circ\\y = 54.6^\circ$

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vampirchik [111]

Answer:

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Step-by-step explanation:

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