To solve for a number x,
3x+4x-2=15
7x-2=15
7x=17
x=2 3/7
or x=~2.43
was one of your answer choices either of the first two equations?

So she need at least 9 cans.
Answer:
A regular polygon is a polygon that is equilateral and equiangular.
The only regular quadrilateral is the square.
We know that all the interior angles of a square are 90° each, so we are fine with that.
Now, for the exterior angles.
If we fix our position in the vertex, we can do from one side, to the same side, a full rotation of 360°.
Now, if we only do an external rotation, this means, from one side to other side, we will do a rotation of 360° minus the interior angle:
this is:
360° - 90° = 270°
Below is an image as a guide of this.
the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.
multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.
so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5 <----- notice, current coefficient times 3 divided by 4+1.
anyhow, with that out of the way, lemme proceed in this one.

so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.
so then, we know that the expanded 2nd term is 24x therefore

we also know that the expanded 3rd term is 240x², therefore we can say that

but but but, we know what "n" equals to, recall above, so let's do some quick substitution
![\bf a^2n^2-a^2n=480\qquad \boxed{n=\cfrac{24}{a}}\qquad a^2\left( \cfrac{24}{a} \right)^2-a^2\left( \cfrac{24}{a} \right)=480 \\\\\\ a^2\cdot \cfrac{24^2}{a^2}-24a=480\implies 24^2-24a=480\implies 576-24a=480 \\\\\\ -24a=-96\implies a=\cfrac{-96}{-24}\implies \blacktriangleright a = 4\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ n=\cfrac{24}{a}\implies n=\cfrac{24}{4}\implies \blacktriangleright n=6 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20a%5E2n%5E2-a%5E2n%3D480%5Cqquad%20%5Cboxed%7Bn%3D%5Ccfrac%7B24%7D%7Ba%7D%7D%5Cqquad%20a%5E2%5Cleft%28%20%5Ccfrac%7B24%7D%7Ba%7D%20%5Cright%29%5E2-a%5E2%5Cleft%28%20%5Ccfrac%7B24%7D%7Ba%7D%20%5Cright%29%3D480%20%5C%5C%5C%5C%5C%5C%20a%5E2%5Ccdot%20%5Ccfrac%7B24%5E2%7D%7Ba%5E2%7D-24a%3D480%5Cimplies%2024%5E2-24a%3D480%5Cimplies%20576-24a%3D480%20%5C%5C%5C%5C%5C%5C%20-24a%3D-96%5Cimplies%20a%3D%5Ccfrac%7B-96%7D%7B-24%7D%5Cimplies%20%5Cblacktriangleright%20a%20%3D%204%5Cblacktriangleleft%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20n%3D%5Ccfrac%7B24%7D%7Ba%7D%5Cimplies%20n%3D%5Ccfrac%7B24%7D%7B4%7D%5Cimplies%20%5Cblacktriangleright%20n%3D6%20%5Cblacktriangleleft)