Answer:
8r^4
Step-by-step explanation:
√(64r^8) = √((8r^4)^2) = 8r^4
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You can make use of either or both of these rules of exponents:
(a^b)^c = a^(b·c) . . . . . used above
Using the second rule, you can write the expression as ...
What is the solution to the system of equations? Use the substitution method. y=2x+4 3x−6y=3
1 answer:
Since the first equation gives you an expression for y, it is convenient to use that in the second equation. Since the second equation has a factor of 3 that can be removed from all terms, it may make the math easier to do that.
Revised 2nd equation:
.. x -y = 1
Substituting for y:
.. x -(2x +4) = 1 . . . . . use the expressiion for y in place of y
.. -x -4 = 1 . . . . . . . . . simplify
.. -4 = 1 +x . . . . . . . . . add x
.. -5 = x . . . . . . . . . . . subtract 1
y = 2x +4
.. = 2(-5) +4
.. = -6
The solution is (x, y) = (-5, -6).
Revised 2nd equation:
.. x -y = 1
Substituting for y:
.. x -(2x +4) = 1 . . . . . use the expressiion for y in place of y
.. -x -4 = 1 . . . . . . . . . simplify
.. -4 = 1 +x . . . . . . . . . add x
.. -5 = x . . . . . . . . . . . subtract 1
y = 2x +4
.. = 2(-5) +4
.. = -6
The solution is (x, y) = (-5, -6).
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