Answer:
those are pretty good! all a's and b's are good! Keep up the good work!!
Step-by-step explanation:
We have been given graph of a downward opening parabola with vertex at point
. We are asked to write equation of the parabola in standard form.
We know that equation of parabola in standard form is
.
We will write our equation in vertex form and then convert it into standard form.
Vertex for of parabola is
, where point (h,k) represents vertex of parabola and a represents leading coefficient.
Since our parabola is downward opening so leading coefficient will be negative.
Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:




Divide both sides by 
So our equation in vertex form would be
.
Let us convert it in standard from.



Therefore, the equation of function is standard form would be
.
Answer:
do we have to put an whole number there
Answer:
Θ = 157.7°
Step-by-step explanation:
Given
cosΘ = - 0.925
Since cosΘ < 0 then Θ is in the second or third quadrant.
Since 0° ≤ Θ ≤ 180° then Θ is in the second quadrant. thus
Θ =
(- 0.925) = 157.7° ← angle in second quadrant
30+3
11*3
10*3+3
60-30+3
(sorry if these didn't help i'm a beginner and i'm in 7th grade)