What is 7/3 % 3/5 thanks

Mathematics

1 answer:

Korolek [52]2 years ago

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What do you mean suhdbebejsjdudbdndndhdnnd

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Shawna and lea left the mall at the same time . They traveled in opposite directions. Lea traveled 30 mph faster that Shawna. Af

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Answer:88

Step-by-step explanation:

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Show your work. What is 93 divided by 3 using repeated subtraction.

tamaranim1 [39]

To use repeated subtraction, you could keep subtracting 3 until you reach 0.
So, we can do
93-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3-3=0
This has 31 -3s,
So 91/3 is 31.

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Is o a integer but not a whole number

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Zero is actually a whole number, rational number, and integer, but it is not a natural number

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If M <1 = 115 degrees what is m <2

SIZIF [17.4K]

Answer:

M<2= 65

Step-by-step explanation:

The reason it is 65 because 2 angles add up to either 90 or 180 and in this case it would be 180.

You would use angle addition postulate to find the answer so M<1 + M<2 = 180.

Since M<1 is 115 you would substitute it into the formula so 115 + M<2 = 180

Then you would subtract 115 from 180 in which you would get M<2 = 65

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3 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

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3 years ago

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