0.139 times what number could get me to 100? PLEASE ANSWER, FAST

property of real numbers that states that the order in which numbers are added or multiplied dose not change the value

timurjin [86]

Answer:

"Commutative property of addition and of multiplication"

Step-by-step explanation:

This is the "commutative property" of addition and of multiplication. That as its name indicates tells us for additions, that if we add A + B, or B + A, we should get the same result. Similarly, the "commutative property" of multiplication tells us that if we perform the product A * B we should get the same answer as if we perform the product: B * A.

7 0

3 years ago

Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +

Veronika [31]

Answer:

Verified

$y(x) = \frac{3Ln(x) + 3}{x}$

$y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}$

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

$x^2y' +xy = 3$

- A general solution to the above ODE is also given as:

$y = \frac{3Ln(x) + C }{x}$

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

$y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x) }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}$

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

$-\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3$

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

$y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3$

- Therefore, the complete solution to the given ODE can be expressed as:

$y ( x ) = \frac{3Ln(x) + 3 }{x}$

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

$y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)$

- Therefore, the complete solution to the given ODE can be expressed as:

$y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}$

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6 0

2 years ago

taras car accelerated from 10 miles per hour to 70 miles per hour in 12 seconds. what is the approximate rate of change in the m

Rina8888 [55]

Answer:

60 mph

Step-by-step explanation:

70 - 10 = 60 miles per hour

5 0

2 years ago

If the area of a triangular kite is 6 square feet and its base is 4 feet, find the height

KonstantinChe [14]

The height of the kite is 3 feet. Here’s
why;
We know that BH=2A (base times height is equal to 2 times the area) of any given triangle.
Lets plug in values;
BH=2A
4(H)=2(6)
Then simplify;
4(H)=12
Flip the equation to find the missing value;
12 divided by 4 is 3.
Check your work;
4(3)=6(2):
12=12
The height of the kite is 3 feet.

4 0

2 years ago

Find the distance between J and K.

Viefleur [7K]

A graph can help you find the appropriate choice to be

... B. 8.49

4 0

2 years ago