The size of the sample they should take to estimate p with a 2% margin of error and 90% confidence is n = 1691.
In statistics, the margin of error is just the degree of a significant error in the outcomes of random sample surveys.
The formula of margin error is, E = z√((p-vector)(1 - (p-vector)) ÷ n)
E = 2% = 0.02
Confidence level = 90%
Now, the proportion is not given so adopt nominal (p-vector) = 0.05
The critical value at CL of 90% is 1.645.
Thus, making n the subject,
n = z²(((p-vector) × (1 - (p-vector))) ÷ E²)
n = 1.645²((0.5 × 0.5) ÷ 0.02²)
n = 1691.266
n ≈ 1691
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35/91
5.7/13.7
5/13
Answer:
Rhombus Side = sqr root [(34 / 2)^2 + (30 / 2)^2]
Rhombus Side = sqr root [17^2 + 15^2]
Rhombus Side = sqr root [289 + 225}
Rhombus Side = sqr root [514]
Rhombus Side = 22.6715680975
Rhombus Perimeter = side * 4 = 90.68627239 cm
Step-by-step explanation:
If you would like to know how many kilograms of fruit do you have, you can calculate this using the following steps:
3 4/5 kg of cherries + 2 1/4 kg of strawberries = 3 4/5 + 2 1/4 = 19/5 + 9/4 = 76/20 + 45/20 = (76 + 45) / 20 = 121/20 = 6 1/20 kg of fruit
The correct result would be 6 1/20 kilograms of fruit.
Answer:
$5.44
Step-by-step explanation:
$1.75 + $1.26 + $1.08 + $0.52 = $4.56
$10.00 - $4.56 = $5.44